implement function as object in PHP

Question

Is it possible to implement functions as object instances in PHP? I'm used to doing this in Java with the code below, but I can't seem to find a similar approach in PHP. Is it possible?

interface OneVarFunction {
    public int eval(int x);
}
static void routine() {
    OneVarFunction func1 = new OneVarFunction() {
        public Boolean eval(int x) {
            return x*x;
        }
    };
    OneVarFunction func2 = new OneVarFunction() {
        public Boolean eval(int x) {
            return 2*x+1;
        }
    };
}

Franz Gleichmann · Accepted Answer · 2017-02-14 07:43:22Z

2

It is possible in PHP7+

in your case, an example would be

interface OneVarFunction {
    public function eval($x);
}

//...

$test = new class implements OneVarFunction {
    public function eval($x) {
        return $x*$x;
    }
};

For more information, see the corresponding site of the PHP Manual, which also provides further examples.

It is not possible in versions prior to PHP7, though.

answered Feb 14, 2017 at 7:43

Franz Gleichmann

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