I have an array that could be made up of any the following values:
input = ['S-1','S-2','S-3','S-4','S-5','S-6','S-7','S-8'];
'input' can be made of any # of these values, without any duplicates. I'm trying to figure out how to sort 'input' according to the order of 'sortingArray':
sortingArray = ["S-1", "S-5", "S-2", "S-6", "S-3", "S-7", "S-4", "S-8"];
Any help would be greatly appreciated.
You can also use filter function and get copy of sortingArray including only values from input:
var input = ['S-1','S-2','S-3','S-4','S-5'];
var sortingArray = ["S-1", "S-5", "S-2", "S-6", "S-3", "S-7", "S-4", "S-8"];
var result = sortingArray.filter((el)=>(input.indexOf(el) > -1));
console.log(JSON.stringify(result));
input only zero or one element of sortingArray exists.Build a look-up object from your "sorting array":
var indexes = sortingArray.reduce(function(lookup, key, index) {
lookup[key] = index;
return lookup;
}, {});
Now you can use that in a comparator function:
input.sort(function(k1, k2) {
return indexes[k1] - indexes[k2];
});
Simple use with for loop.And apply the if condition for half of the array length.Then pass with new array
var input = ['S-1','S-2','S-3','S-4','S-5','S-6','S-7','S-8'];
var c =eval(input.length/2);
arr=[];
for(var i=0; i<input.length; i++){
if(i < c)
{
arr.push(input[i]);
arr.push(input[i+c]);
}
}
console.log(arr)You could use an object with the indices of the sorted array and sort the new array with it.
var input = ['S-1', 'S-2', 'S-3', 'S-4', 'S-5', 'S-6', 'S-7', 'S-8'],
sortingArray = ["S-1", "S-5", "S-2", "S-6", "S-3", "S-7", "S-4", "S-8"],
order = Object.create(null);
sortingArray.forEach(function (a, i) { order[a] = i; });
input.sort(function (a, b) { return order[a] - order[b]; });
console.log(input);.as-console-wrapper { max-height: 100% !important; top: 0; }