Finding equivalent of imagemagick morphology command with opencv Python

Question

I have an image with horizontal lines in it. An approach that I found that works somewhat well is to use imagemagick to morphology like this.

convert orig.jpg -morphology close:1 "1x7: 1,0,0,0,0,0,1" final.jpg

It is running one iteration of morphology with 1x7 kernel

I'm trying to find equivalent of this in opencv python.

Anthony · Accepted Answer · 2017-02-27 15:55:13Z

1

This command is performing the CLOSING Morphological Operation on the image which can be translated to OpenCV as:

kernel = np.array([1, 0, 0, 0, 0, 0, 1], dtype=np.uint8)  # 1x7: 1,0,0,0,0,0,1
closing = cv2.morphologyEx(img, 
                           cv2.MORPH_CLOSE, # morphology close:1
                           kernel)

edited Feb 27, 2017 at 15:55

Anthony

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answered Feb 27, 2017 at 3:53

ZdaR

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9 Comments

Anthony Over a year ago

I get error

Assertion failed (_kernel.type() == CV_8U) in MorphFilter, file /home/guru/opencv-2.4.10/modules/imgproc/src/morph.cpp, line 791 mitre1.jpg /home/guru/opencv-2.4.10/modules/imgproc/src/morph.cpp:791: error: (-215) _kernel.type() == CV_8U in function MorphFilter

while doing this in opencv using the snippet you provided. if I change np.array([[1,0,0,0,0,0,1]]) to np.ones((1,1)) then it works fine. Any thoughts?

ZdaR Over a year ago

Sorry @Anthony missed something obvious there, Edited.

Anthony Over a year ago

Thanks! that worked! however, I'm not getting results anywhere close to what imagemagik provides. original img, converted from imagemagik, converted from opencv

Anthony Over a year ago

FWIW i got the imagemagik command from here imagemagick.org/discourse-server/viewtopic.php?p=92969#p92969 which explains what the command is doing in detail

ZdaR Over a year ago

Oh that was really Helpful.

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