Replace numbers with array

Question

how to put integer values, taken by another array, instead of 1,2,3 like this?

$arr_id = array(1,2,3); //this arr_id go to line 2 instead of 1,2,3
'id' => array('$in' => array(1,2,3))

well, putting $arr_id instead of "1,2,3"... something like this

'id' => array('$in' => array($arr_id))

the problem is that 1,2,3 are number, but in my $arr_id i've strings. If i try to convert string to int i've a problem with "," too

here

array($arr_id))

i need to have integers (not string) taken by $arr_id, separated by ","...

It looks like they're already integers. Are you saying that $arr_id is actually equal to the string "1,2,3"? Can you clarify with code examples exactly what you're starting with and what you want to end up with? — Don't Panic
– Don't Panic, Commented Mar 15, 2017 at 20:06
Or is it already an array of ints and you're trying to turn it into "1,2,3"? — Don't Panic
– Don't Panic, Commented Mar 15, 2017 at 20:08
@Don'tPanic i'm tryin' to put it inside 1,2,3 in the line 'id' => array('$in' => array(1,2,3)). It starts with a string (verified by echo gettype($arr_id);) . Please read below in the first answer and relative comments... there's a progression :) — flexicon
– flexicon, Commented Mar 15, 2017 at 20:27
if i wrote 'id' => array('$in' => array($array_replaced[1])) or 'id' => array('$in' => array($array_replaced[2])) the code works fine. But i can't write [integers. Very strange problem.... — flexicon
– flexicon, Commented Mar 15, 2017 at 20:31
I'd really like to help. But I don't really understand from your description what you're starting with or what you want to end up with. Can you edit your question to add a code example that shows that? — Don't Panic
– Don't Panic, Commented Mar 15, 2017 at 20:36

Neil · Accepted Answer · 2017-03-15 19:53:01Z

1

You can convert a string array to an int array in PHP using:

$arr_id_str = array("1","2","3");
var_dump(array_map('intval',$arr_id_str));

answered Mar 15, 2017 at 19:53

Neil

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1 Comment

flexicon Over a year ago

ok... your code is correct but... there's a problem: if i put $array_replaced $array_replaced = array_map('intval',$arr_id_str); inside 'id' => array('$in' => array($array_replaced)) the code doesn't work Warning: array_values() expects parameter 1 to be array, null given i can't write $array_replaced[1] or 2 or 3... 'cause is the same to write 1,2,3. This fields is dynamic.....

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