Use additional array in php foreach

Question

I would really appreciate your help.

I want to use an additional array with foreach.

Currently it looks like this and works perfectly.

<?php

$listcity = array("Negril" => "negril",
"Kingston" => "kingston",
"Ocho Rios" => "ocho-rios");

foreach ($listcity as $cityname => $citylink) {
    echo "<li data-name=\"$cityname Hotels\"><a href=\"https://example.com/hotels/$citylink\">$cityname</a></li>";
}
?>

Now I want to add a span with the following numbers:

 $distancemiles = array("Negril" => "25",
  "Kingston" => "10",
  "Ocho Rios" => "67");

I want the final echo to be the following:

<li data-name=\"$cityname Hotels\"><a href=\"https://example/hotels/$citylink\">$cityname</a><span>(HERE THE DISTANCE IN MILES miles)</span></li>

so that the browser outputs for instance:

Negril (50 miles)

So I would like to know how I can combine my three sources of data:

$cityname --> Should be the name of the city
$citylink --> Should be the link ending
$distancetocity --> Should be the distance

Would someone help me with this? I've tried very hard to make it work and read through all kinds of online tutorials, but I fail every time.

Best,

Max

how do you get the array ?

hassan
– hassan

2017-03-17 16:51:21 +00:00
Commented Mar 17, 2017 at 16:51 — hassan
– hassan, Commented Mar 17, 2017 at 16:51

Mohammad · Accepted Answer · 2017-03-17 16:53:05Z

1

You can find distance of city by it name. The $distancemiles[$cityname] return distance of city.

foreach ($listcity as $cityname => $citylink){
    echo "<li data-name=\"$cityname Hotels\">
        <a href=\"https://example.com/hotels/$citylink\">$cityname</a>
        <span>$distancemiles[$cityname]</span>
    </li>";
}

See result of code in demo

answered Mar 17, 2017 at 16:53

Mohammad

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Comments

Patrick Murphy · Accepted Answer · 2017-03-17 16:53:12Z

1

<?php

$listcity = array("Negril" => "negril",
"Kingston" => "kingston",
"Ocho Rios" => "ocho-rios");

$distancemiles = array("Negril" => "25",
  "Kingston" => "10",
  "Ocho Rios" => "67");

foreach ($listcity as $cityname => $citylink) {
    echo "<li data-name=\"$cityname Hotels\"><a href=\"https://example/hotels/$citylink\">$cityname</a><span>($distancemiles[$cityname])</span></li>";
}
?>

You can look up the value of the miles using your distance array.

Your array list city array has structure cityname->linkname your distance array has structure cityname->distanceInMiles so you can use the city name from your for loop to look up the distance at the index of the cityname.

answered Mar 17, 2017 at 16:53

Patrick Murphy

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Comments

Pipe · Accepted Answer · 2017-03-17 16:53:54Z

1

Then you can do:

echo "<li data-name=\"$cityname Hotels\"><a href=\"https://example.com/hotels/$citylink\">$cityname</a><span>{$distancemiles[$cityname]}</span></li>";

answered Mar 17, 2017 at 16:53

Pipe

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hassan · Accepted Answer · 2017-03-17 17:00:52Z

1

using arrray_merge_recursive :

merge your array into one array, then access it as follows:

$listcity = array("Negril" => "negril",
"Kingston" => "kingston",
"Ocho Rios" => "ocho-rios");

$distancemiles = array("Negril" => "25",
  "Kingston" => "10",
  "Ocho Rios" => "67");

$oneArray = array_merge_recursive($listcity, $distancemiles);


foreach ($oneArray as $cityname => $citylink) {
    echo "<li data-name=\"$cityname Hotels\"><a href=\"https://example/hotels/".$citylink[0]."\">$cityname</a><span>".$citylink[1]."</span></li>";
}

live example: https://3v4l.org/Q0VDn

edited Mar 17, 2017 at 17:00

answered Mar 17, 2017 at 16:54

hassan

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Comments

Tom Udding · Accepted Answer · 2017-03-17 16:53:55Z

0

If you add a reference to the $distancemiles array with $cityname as key (like $distancemiles[$cityname]) you can get the miles within the foreach loop.

$listcity = array(
    "Negril" => "negril",
    "Kingston" => "kingston",
    "Ocho Rios" => "ocho-rios");

$distancemiles = array("Negril" => "25",
  "Kingston" => "10",
  "Ocho Rios" => "67");

foreach ($listcity as $cityname => $citylink) {
    echo "<li data-name=\"$cityname Hotels\"><a href=\"https://example.com/hotels/$citylink\">$cityname</a><span>$distancemiles[$cityname]</span></li>";
}

// Negril25
// Kingston10
// Ocho Rios67

answered Mar 17, 2017 at 16:53

Tom Udding

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