I am trying to make a program that converts a given integer(limited by the value 32 bit int can hold) into 32 bit binary number. For example 1 should return (000..31times)1. I have been searching the documents and everything but haven't been able to find some concrete way. I got it working where number of bits are according to the number size but in String. Can anybody tell a more efficient way to go about this?
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1Possible duplicate of python convert to binary and keep leading zerosJosh Kelley– Josh Kelley2017-03-26 02:41:18 +00:00Commented Mar 26, 2017 at 2:41
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Can you show us some codejc22920– jc229202017-03-26 02:43:46 +00:00Commented Mar 26, 2017 at 2:43
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Are you looking for 2's complement representation?Jithin Pavithran– Jithin Pavithran2017-03-26 05:10:46 +00:00Commented Mar 26, 2017 at 5:10
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Yes, I want this representation because I am trying to build an webapp which mimics the Assembler(with limited functionality)Pooja Gupta– Pooja Gupta2017-03-27 04:13:30 +00:00Commented Mar 27, 2017 at 4:13
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5 Answers
'{:032b}'.format(n) where n is an integer. If the binary representation is greater than 32 digits it will expand as necessary:
>>> '{:032b}'.format(100)
'00000000000000000000000001100100'
>>> '{:032b}'.format(8589934591)
'111111111111111111111111111111111'
>>> '{:032b}'.format(8589934591 + 1)
'1000000000000000000000000000000000' # N.B. this is 33 digits long
3 Comments
Pooja Gupta
But this returns a string,I need a binary number because I want to add features like left shift and right shift also.
juanpa.arrivillaga
@PoojaGupta You are looking for an
int
Scott
How about converting negative values?
You can just left or right shift integer and convert it to string for display if you need.
>>> 1<<1
2
>>> "{:032b}".format(2)
'00000000000000000000000000000010'
>>>
or if you just need a binary you can consider bin
>>> bin(4)
'0b100'
Comments
x = 1234
print(f"{x:032b}") # 00000000000000000000010011010010
Comments
Say for example the number you want to convert into 32 bit binary is 4. So, num=4. Here is the code that does this: "s" is the empty string initially.
for i in range(31,-1,-1):
cur=(num>>i) & 1 #(right shift operation on num and i and bitwise AND with 1)
s+=str(cur)
print(s)#s contains 32 bit binary representation of 4(00000000000000000000000000000100)
00000000000000000000000000000100
Comments
Lets say
a = 4
print(bin(a)) # 0b101
For the output you may append 0s from LSB to till 101 to get the 32bit address for the integer - 4. If you don't want 0b you may slice it
print(bin(a)[-3:]) # 101
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