How to output an array object when the rest of its array objects are selected?

Question

With my code as an example below, I'd like to know how to output PRIZE if TYPE, COLOR and SIZE is selected. (e.g.) $type='apple', $color='green', $size='medium' and the OUTPUT is 14. Thanks!

$fruits = [

    ['type' => apple, 'color' => 'green' , 'size' => 'small' , 'prize' => 10],

    ['type' => apple, 'color' => 'red' , 'size' => 'medium' , 'prize' => 12],

    ['type' => apple, 'color' => 'green' , 'size' => 'medium' , 'prize' => 14]

];

LF-DevJourney · Accepted Answer · 2017-03-26 06:31:37Z

2

Use array_filter to filter the array.

$result = array_filter($fruits, function($v) use ($selected){
    return ($v['type'] == $selected['type']) && ($v['color'] == $selected['color']) && ($v['size'] == $selected['size']) ? true : false;
});
print_r($result);

answered Mar 26, 2017 at 6:31

LF-DevJourney

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1 Comment

HKT Over a year ago

Thanks Kris! I will be using this on Wordpress and return the result asynchronously on a Form. By the way, I will be loading up about 40 rows of TYPE, COLOR, SIZE and PRICE. Any advice on how I could put all of those on my array? Sorry still a newbie :)

Benjamin Diaz · Accepted Answer · 2017-03-26 06:40:43Z

1

function getFruitPrice($type, $color, $size) {
    for(int $i = 0; $i < count($fruits); $i++) {
      if($fruits[$i]['type'] == $type &&
         $fruits[$i]['color'] == $color &&
         $fruits[$i]['size'] == $size) {
             return $fruits[$i]['price'];
         }
    }
}

answered Mar 26, 2017 at 6:40

Benjamin Diaz

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