Python: check regex expression [duplicate]

Question

I generate my own regex expression and I would like to check if it is valid. For example if I have regex "[a-zA-Z0-9]" it will be valid but "[a-zA-Z0s-9]" not.

Using re.compile()? You could do that in a try/except block (and catch re.error). — gen_Eric
– gen_Eric, Commented Mar 29, 2017 at 21:15
Also, what do you mean by "generate my own regex"? Are you dynamically generating regexes? — gen_Eric
– gen_Eric, Commented Mar 29, 2017 at 21:32
Yes... I generate own regexes according to some pattern. But sometimes it makes mistakes, so I want to catch that a generate my warning to stderr with exit code. — Honza
– Honza, Commented Mar 29, 2017 at 21:47

Aaron Brock · Accepted Answer · 2017-03-29 21:29:56Z

1

To check if regex is valid from inside python:

import re
re.compile('<regex>')

This code will throw an error if it's invalid regex.

However, I find it much more useful to use regex tool, here's a few to choose from:

answered Mar 29, 2017 at 21:29

Aaron Brock

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3 Comments

Honza Over a year ago

I want to catch invalid regex a generate my warning to stderr with exit code.

Honza Over a year ago

solved. thank you for help and hint! :)

Aaron Brock Over a year ago

You'll just need to surround it in a try except :)

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