how to implement a partial view with generic type inference

Question

I am working through this sample and came across a problem. To implement pagination, the sample extends list and adds pagination to it. This list is then used as the model.

In my view I want to add a pagination control. In the sample they simply add it to the page but I want to make it a user control because I plan to implement pagination in multiple pages. Off course This has to be a strongly typed view but since I can't use wildcards in C# I can not implement it like this:

<%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<PaginatedList<?>>" %>

Since I only plan to use the members declared in PaginatedList and not in List I don't need the type.

In a C# method we could solve this problem with type inference but how is it don in a partial view?

tvanfosson · Accepted Answer · 2010-12-01 13:04:26Z

3

Define an interface containing the pagination properties that you want to use in your partial view. Have your PaginatedList<T> class implement this interface. Have your partial view be typed to the interface.

public interface IPaginated
{
    int PageIndex  { get; }
    int PageSize   { get; }
    int TotalCount { get; }
    int TotalPages { get; }
}

public class PaginatedList<T> : List<T>, IPaginated
{
   ... should not need to change ...
}

<%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<IPaginated>" %>

answered Dec 1, 2010 at 13:04

tvanfosson

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