replace multiple values in a string with multiple sources

Question

I have a pixel like:

<img src='http://www.montag.com/directory_folder/tracking_noip.php?tracking=[ID_MTG]&data=[TEL]' height='1' width='1' border='0'/>

I need to replace the keys [TEL] and [ID_MTG] with the value I receive from a script. For example if I have:

$tel = "0613321223";
$id_mtg = "4875";
$email = "[email protected]";

I need to output:

<img src='http://www.montag.com/directory_folder/tracking_noip.php?tracking=4875&data=0613321223' height='1' width='1' border='0'/>

If I have:

<img src='http://www.montag.com/directory_folder/tracking_noip.php?tracking=[ID_MTG]&data=[EMAIL]' height='1' width='1' border='0'/>

I need to ouput:

<img src='http://www.montag.com/directory_folder/tracking_noip.php?tracking=4875&[email protected]' height='1' width='1' border='0'/>

I have:

$tel = "0613357221";
$email = "[email protected]";
$id_mtg = "560";

$string = "<img src='http://www.montag.com/directory_folder/tracking_noip.php?tracking=[TEL]&data=[ID_MTG]' height='1' width='1' border='0'/>";
$patterns = array();
$patterns[0] = ' /\[TEL\]/ ';
$patterns[1] = ' /\[EMAIL\]/ ';
$patterns[2] = ' /\[ID_MTG\]/ ';
$replacements = array();
$replacements[2] = $id_mtg;
$replacements[1] = $email;
$replacements[0] = $tel;
echo htmlentities(preg_replace($patterns, $replacements, $string));

But my string is:

<img src='http://www.montag.com/directory_folder/tracking_noip.php?tracking=520&data=0613357221' height='1' width='1' border='0'/>

The order is reversed.

I don't see the need for regular expressions if you search for fixed strings. Have you tried strtr? — Álvaro González
– Álvaro González, Commented Apr 10, 2017 at 16:39

Bhaumik Pandhi · Accepted Answer · 2017-04-10 16:46:38Z

3

$str = 'hi all, I said hello';

$replace_pairs = array(
  'all' => 'everybody',
  'hello' => 'hey',
);

echo strtr($str, $replace_pairs);

This would help you.

answered Apr 10, 2017 at 16:46

Bhaumik Pandhi

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Comments

AbraCadaver · Accepted Answer · 2017-04-10 17:20:47Z

1

The order is wrong because you defined your $replacements in reverse order. Even though you specified indexes in descending order, the order in which you created the array is preserved. Check this with print_r($replacements);. You could sort by keys with ksort() if needed to get the array in the proper order.

But for this application, strtr() or str_replace() makes more sense. Make sure to define the arrays in the same order:

$search  = array('[TEL]', '[EMAIL]', '[ID_MTG]');
$replace = array($tel, $email, $id_mtg);

$result = str_replace($search, $replace, $string);

edited Apr 10, 2017 at 17:20

answered Apr 10, 2017 at 16:51

AbraCadaver

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1 Comment

Buck Over a year ago

I look at this solution after the train but it seems to me perfectly do the trick! I think i search too far ^^

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