Illegal string offset for array within an array

Question

I have the main array called $quizzes which contains the collection of $Quiz. Each $Quiz has the following fields: $Quiz['correct'] gives me the number of correct questions.

I can get the number of correct questions for 12th quiz using $quizzes[12]['correct']

However, since these quizzes are not displayed in order, I decided to define a new array:

$listoftests = array('$quizzes[30]','$quizzes[51]');

In my head, $listoftests[0]['correct'] should be equal to $quizzes[30]['correct'] but it's giving me

Warning: Illegal string offset 'correct' in /demo.php on line 14 $

when I try to echo $listoftests[0]['correct'];

what are you trying to there is n offset correct

M A SIDDIQUI
– M A SIDDIQUI

2017-04-11 10:54:17 +00:00
Commented Apr 11, 2017 at 10:54 — M A SIDDIQUI
– M A SIDDIQUI, Commented Apr 11, 2017 at 10:54

Sahil Gulati · Accepted Answer · 2017-04-11 10:56:31Z

1

In this $listoftests = array('$quizzes[30]','$quizzes[51]'); These are considered as two strings $quizzes[30] and $quizzes[51]. You should remove single quotes ' and try again.

Change this:

$listoftests = array('$quizzes[30]','$quizzes[51]');

To:

$listoftests = array($quizzes[30],$quizzes[51]);

answered Apr 11, 2017 at 10:56

Sahil Gulati

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Comments

Dmitriy Troian · Accepted Answer · 2017-04-11 10:55:57Z

1

By doing this

$listoftests = array('$quizzes[30]','$quizzes[51]');

you created array of 2 strings. That's it. Not an array of arrays.

You should remove quotes. And you can also use isset() to check if array item exists.

answered Apr 11, 2017 at 10:55

Dmitriy Troian

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Karim · Accepted Answer · 2017-04-11 11:01:37Z

1

Remove the single quote and it shell work fine $listoftests = array($quizzes[30],$quizzes[51]);

answered Apr 11, 2017 at 11:01

Karim

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lazyCoder · Accepted Answer · 2017-04-11 11:06:54Z

1

@GRS you can do it in two way:

//case one where the element will be of string type
<?php
  $quizzes[30] = 3;
  $quizzes[51] = 32;
  $listoftests = array("$quizzes[30]","$quizzes[51]");
  var_dump($listoftests);

  //or

 //case two where the element will be of integer type
 <?php
  $quizzes[30] = 3;
  $quizzes[51] = 32;
  $listoftests = array($quizzes[30],$quizzes[51]);
  var_dump($listoftests);

answered Apr 11, 2017 at 11:06

lazyCoder

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