PHP array_search bug?

Question

I was trying to find a value in a multi-array variable. It took too much time to find where was my bug...

Try this code:

$aa = array("nombre" => "HOLA", "v" => 0);
$bb = array("nombre" => "HOLB", "v" => 0);
$cc = array("nombre" => "HOLC", "v" => 0);
$dd = array($aa,$bb,$cc);

if (in_array("HOLA",array_column($dd,"nombre")))
     echo "in_array = yes";
else
     echo "in_array = no";

echo "<br>";

if (array_search("HOLA",array_column($dd,"nombre")))
     echo "array_search = yes";
else
     echo "array_search = no";

the answer I get is:

in_array = yes
array_search = no

It is this a supposed behavior?

Yes, it is expected behaviour; because it's finding the value at key 0, which you're then testing for truthinesss, and 0 == false. Use if (array_search("HOLA",array_column($dd,"nombre")) !== false) — Mark Baker
– Mark Baker, Commented May 9, 2017 at 16:19

Jeff Lambert · Accepted Answer · 2017-05-09 16:20:11Z

2

Yes. The documentation for array_search states the following:

Warning: This function may return Boolean FALSE, but may also return a non-Boolean value which evaluates to FALSE. Please read the section on Booleans for more information. Use the === operator for testing the return value of this function.

The value you are getting is 0, which is failing your if, but is the correct answer.

answered May 9, 2017 at 16:20

Jeff Lambert

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Ali Niaz · Accepted Answer · 2017-05-09 16:26:49Z

1

array_sarch will return the index at which it finds the result, so in your case 'HOLA' is at the 0 index which makes the condition fail. You should check it like this

if (array_search("HOLA",array_column($dd,"nombre")) !== false)

answered May 9, 2017 at 16:26

Ali Niaz

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