Curl command doesn't work in bash script

Question

I am trying to upload a JSON file into my noSQL database using a bash script, but it doesn't work and I don't understand why.

This is the script :

test='{"evaluation": "none"}'
test="'$test'"
command="curl -XPUT localhost:9200/test/evaluation/$i -d $test"
echo "$command"
$command

This is the error :

curl -XPUT localhost:9200/test/evaluation/0 -d '{"evaluation": "none"}'
{"error":"Content-Type header [application/x-www-form-urlencoded] is not supported","status":406}curl: (3) [globbing] unmatched close brace/bracket in column 7

When I do the command given in my command line it works fine though.

What is the error here ? Thank you

See Bash FAQ 50

chepner
– chepner

2017-05-11 15:42:20 +00:00
Commented May 11, 2017 at 15:42 — chepner
– chepner, Commented May 11, 2017 at 15:42

chepner · Accepted Answer · 2017-05-11 15:43:50Z

2

Don't store a command in a variable; if you absolutely must have something usable with logging, put the arguments in an array.

test='{"evaluation": "none"}'
args=( -XPUT localhost9200/test/evaluation/"$i" -d "$test" )
echo "curl ${args[*]}"
curl "${args[@]}"

answered May 11, 2017 at 15:43

chepner

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1 Comment

Chococo35 Over a year ago

thank you ! I've been wondering on the problem for a while and this solution works perfectly

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