Pass argument to shell script through paramiko client.exec_command

Question

I want to pass argument to shell script dynamically through paramiko. I tried but I can't achieve it. If anyone knows please let me know.

Below is my code:

Python code:

client = paramiko.SSHClient()
client.set_missing_host_key_policy(paramiko.AutoAddPolicy())
client.connect("192.168.10.5", username='root', password='root')
backup_name="test_backup"
stdin, stdout, stderr = client.exec_command('./backup.sh',backup_name)
stdin.write('next')
stdin.flush()

Shell Script(backup.sh):

#!/bin/bash

virsh snapshot-create-as one-96 "'$1'"

I want to create backup with the backup name mentioned in the python code through shell script. How to pass that name in exec_command to shell script? Thanks in Advance!!!!

Possible duplicate of Automate ssh connection and execution of program with Python's Paramiko — e4c5
– e4c5, Commented May 24, 2017 at 11:39

Brian · Accepted Answer · 2022-08-10 09:24:35Z

1

To pass arguments to the exec_command, just use the following format:

exec_command(command, bufsize=-1, timeout=None, get_pty=False, environment=None)

For your example(exec_command('./backup.sh',backup_name)) you may do it this way:

exec_command(command='./backup.sh', bufsize=-1, timeout=None, get_pty=False, environment=dict(backup_name=backup_name))

Reference docs

edited Aug 10, 2022 at 9:24

answered Aug 10, 2022 at 9:19

Brian

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