Count specific variables in array

Question

I have two different arrays:

$dep = Array ( [0] => 1 [1] => 1 [2] => 1 [3] => 2 [4] => 3 [5] => 3 )

and

$q1_a = Array ( [0] => 4 [1] => 4 [2] => 4 [3] => 2 [4] => 4 [5] => 2 )

I put it in one array:

$arr = array($dep, $q1_a);

And then I got:

Array ( 
[0] => Array ( [0] => 1 [1] => 1 [2] => 1 [3] => 2 [4] => 3 [5] => 3 ) 
[1] => Array ( [0] => 4 [1] => 4 [2] => 4 [3] => 2 [4] => 4 [5] => 2 ) )

How can I summarize variables of second array where it matches specific number in first. So I need to find sum of numbers where first array has 1,2 and 3. And to get 3 different numbers.

so first number will be:

[0] => 1 [1] => 1 [2] => 1
[0] => 4 [1] => 4 [2] => 4 
4+4+4=12

second:

[3] => 2
[3] => 2
2

third:

[4] => 3 [5] => 3
[4] => 4 [5] => 2
4+2=6

How can I do that?

LF-DevJourney · Accepted Answer · 2017-06-12 02:12:32Z

2

Try this, live demo.

<?php
$dep = [1,1,1,2,3,3];
$q1_a = [4,4,4,2,4,2];

$flag = current($dep);
$result = [0];
foreach($dep as $k => $v){
  if($flag == $v) {
    $val = end($result);
    $result[key($result)]= $val + $q1_a[$k];
  }
  else
    $result[] = $q1_a[$k];
  $flag = $v;
}
print_r($result);

answered Jun 12, 2017 at 2:12

LF-DevJourney

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Comments

Felix · Accepted Answer · 2017-06-12 02:14:25Z

0

$cur_index = null;  
$result = [];
$j = 0;
for ( $i = 0; $i < length($dep); $i++) {  
  if ($cur_index == null){ 
    $result[$j] = $q1_a[$i];
    $cur_index = $dep[i];
  }
  else if ($cur_index == $dep[$i]) {
    $result[$j] += $q1_a[$i]
  }
  else {
    $cur_index = $dep[i];
    $result[++$j] += $q1_a[$i];
  }   
}

Hope this work and this syntax may not correct.

answered Jun 12, 2017 at 2:14

Felix

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