PHP not identifying ajax call

Question

I have a PHP script which is displaying a drop-down box.Now when I select a drop down box an ajax call is made to the PHP script , which works fine , I can see in firebug that the call has been made and correct parameter is passed.I am using this code in php to identify if the call has been made

isset($_SERVER['HTTP_X_REQUESTED_WITH']) && 
       ($_SERVER['HTTP_X_REQUESTED_WITH'] == 'XMLHttpRequest')

But this check always fails and I do not get any response.How can I debug this?

And what value is actually in $_SERVER['HTTP_X_REQUESTED_WITH']? — zerkms
– zerkms, Commented Dec 16, 2010 at 4:40

The Scrum Meister · Accepted Answer · 2010-12-16 04:40:56Z

2

did you check in firebug -net tab - if the header HTTP_X_REQUESTED_WITH is being sent?

answered Dec 16, 2010 at 4:40

The Scrum Meister

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4 Comments

Aditya Shukla Over a year ago

@scrum awesome , I do not see it anywhere in header sub tab of the net tab in firebug.I have read that $_SERVER is not a php variable but is generated by the web server , so if it generated by webserver then how can we control it?

The Scrum Meister Over a year ago

$_SERVER is a php variable that gets populated by the server. what are you using to sent the AJAX call?

Aditya Shukla Over a year ago

@scrum I am using this code , i am not sure if i should set the header or not.xmlhttp.open("GET","index.php?name="+name,true); //xmlhttp.setRequestHeader('Content-Type','application/x-www-form-urlencoded'); xmlhttp.send();

The Scrum Meister Over a year ago

by default it will not send the header. use xmlhttp.setRequestHeader('X_REQUESTED_WITH','XMLHttpRequest');

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