I have array:
var data = [];
data.genre = [ 'AAAA', '2', 'CCCc', '3', 'dDdDD' ];
a need to remove all string from array and return only numbers...so above return i need to be:
data.genre = [ '2', '3' ];
I try with this:
alert(data.genre.map(function(x){ return x.replace(/^\d+\.\s*/,"") }));
But nothing is changed...so i need to make whole array remove strings and leave only numbers...this i need to get id with this numbers in my mysql left join genre on id.
Use Array#filter():
var data = {};
data.genre = [ 'AAAA', '2', 'CCCc', '3', 'dDdDD', '', ' ' ];
data.genre = data.genre.filter(function (str) {
return str.trim() && !isNaN(str);
});
console.log(data.genre);This method uses the global function isNaN() to determine if the string can be coerced to a numerical value. If not, isNaN() returns true so we must negate ! that, in order to filter numeric strings. In addition, it preflights this check with String#trim(), and empty strings evaluated as a Boolean are falsy, so strings with whitespace only shall not pass.
Another comment, make sure that you declare data as an object {} instead of an array [] if you're going to assign it arbitrary properties. Arrays are used for storing ordered data.
You could filter with a regular expression which test for digits only.
var data = {};
data.genre = [ 'AAAA', '2', 'CCCc', '3', 'dDdDD' ];
data.genre = data.genre.filter(function (a) {
return /^\d+$/.test(a);
});
console.log(data);
RegExp.prototype.test is better anyway because it does not create an unused variable.//.test makes a comment.You can use Array.prototype.filter for this. Array.filter takes in a callback function which should return true or false and will composite a new array based on the true/false outputs.
filternotmap.datashould be an object not array?"1.2"?