0

I have an array (paint) where the output looks like this:

array(3) {
   ["id"]=> string(1) "2"
   ["type"]=> string(1) "O"
   ["number"]=> string(1) "1"
}

array(3) {
   ["id"]=> string(1) "3"
   ["type"]=> string(1) "W"
   ["number"]=> string(1) "3"
}
array(3) {
   ["id"]=> string(1) "4"
   ["type"]=> string(1) "W"
   ["number"]=> string(1) "5"
}

Etc.

What I am trying is how often the type field contains W. So in this case I should have an output of 2. He should skip the first because there the type field is O.

What I tried:

 $sum = count($paint["type=W"]);

That doesn't work though. Is it possible to just count how often the type value is W?

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5
  • 1
    $sum = count($paint["type=W"]); maybe a little typo just insert the ] Commented Aug 30, 2017 at 11:05
  • @North-Wind: That might not contain the syntax error but will still not do what Robbert wants. Commented Aug 30, 2017 at 11:06
  • I edited this in my first post. But that is still not working. Commented Aug 30, 2017 at 11:06
  • What is the relation between the subsequent arrays? Is it a 2 dimensional array? Are the arrays retrieved from something? Commented Aug 30, 2017 at 11:07
  • 1
    use array_column and array_count_values to get desired result. Commented Aug 30, 2017 at 11:07

4 Answers 4

Reset to default
1

Try using array_filter:

$typeW = array_filter($array1, fucntion($sub) {
    return $sub['type'] === 'W';
});
echo count($typeW);
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4 Comments

This solution assumes it is a 2D array, we don't know that.
Otherwise the question does not make much sense at all :(
The arrays could be fetched rows from a database. Fetched one by one.
@Robbert: Ah, so it is a 2D array after all, thanks for letting us know.
1

Hope this simple one will be helpful. Here we are using array_column on array to get all the values having key as type and then counting values using array_count_values.

Try this code snippet here

$result=array_count_values(array_column($array,"type"));
print_r($result["W"]);

Output: 2

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Comments

0

What about a simple for loop?

 var count = 0;
 for (var i =0; i< array.length; i++) {
      if($paint[i]['type'] === 'W'){
           count++;
      }
 }
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1 Comment

Now this assumes a 2D array? That information is not in the question.
0

Using a while loop:

<?php
$paint = array();
$i=0;
$x=0;
while($i<count($paint)){
    if($paint[$i][1]=="W"){
        $x++;
    }
    $i++;
}

echo "result: $x"; --> 2

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3 Comments

This is just ugly, why not use a foreach loop?
That's a matter of taste, my friend.
@t1gor: Yes, it is, but also experience. A foreach loop has a build-in counter, you cannot got wrong with that. With a while loop you might get lost in the $x++; - $i++;, mixing them up and cause a difficult bug. A while loop should be used in cases were you don't have a simple counter, even a for loop would be better here because it keeps the counter together in one place.

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