How to append data to an object with Javascript

Question

Heres is how I add data to my object:

    let trade = [
       new RecordStock(elem, recordtime, stockquantity, tradetype, stocksymbol),
   ]

The problem is when I run this:

 console.log(trade[0].price);

It seems that overwrites my object from the beginning.

I add my class code. How i can print the first data from the object

    class RecordStock {

  constructor(price, timestamp, stockquantity, tradetype, stocksymbol) {
    this.price = price;
    this.timestamp = timestamp;
    this.stockquantity = stockquantity;
    this.tradetype = tradetype;
    this.stocksymbol = stocksymbol;
  }
  static recordTrade(){
    console.log(price[0]);
  }
}

What do you mean by overwrite? The object inside the array will stay as is from the time you initialised the array. — Nandu Kalidindi
– Nandu Kalidindi, Commented Nov 26, 2017 at 21:19
@NanduKalidindi when I execute a function and console.log(trade[0]) it always print a different object. Example: Input: price => 100. When I save it in an object it works perfect but when I want save more prices in the object like 101 I want when I print price[0] keeps the number 100 and NO the 101. — Pablo Malynovytch
– Pablo Malynovytch, Commented Nov 26, 2017 at 21:25
I am not sure I fully understand but are you trying to add objects to the trade array as you execute a function? — Nandu Kalidindi
– Nandu Kalidindi, Commented Nov 26, 2017 at 21:29
Yes but I want to push the information creating a new object but not overwrite the data in the object. — Pablo Malynovytch
– Pablo Malynovytch, Commented Nov 26, 2017 at 21:32

Nandu Kalidindi · Accepted Answer · 2017-11-26 22:12:37Z

1

I think you are looking to push objects into the trade array. You can achieve this by simply appending to the array.

You can push objects with something like this

Assuming you have a function that adds the RecordStock object. Here is how it could be.

let trade = [];    

trade.push(new RecordStock(elem, recordtime, stockquantity, tradetype, stocksymbol));

trade.push(new RecordStock(elem, recordtime, stockquantity, tradetype, stocksymbol));

trade.push(new RecordStock(elem, recordtime, stockquantity, tradetype, stocksymbol));

Now you can access the latest RecordStock you pushed using this trade[trade.length - 1]. trade[0] will always contain the object which you pushed first. This is the usual array functionality.

edited Nov 26, 2017 at 22:12

answered Nov 26, 2017 at 21:31

Nandu Kalidindi

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7 Comments

Pablo Malynovytch Over a year ago

the name of the class is called RecordStock

Nandu Kalidindi Over a year ago

Did you initialise trade using let trade = []?

Pablo Malynovytch Over a year ago

no...now works the problem is that iam printing trade[0] that always is the data i put but trade.object[0] i dont know how i can print

Pablo Malynovytch Over a year ago

I have added my class

Nandu Kalidindi Over a year ago

I updated the answer a little. But I am still un clear as to what you want to achieve. Please post a working snippet if this did not solve your issue.

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Pablo Malynovytch · Accepted Answer · 2017-11-27 15:21:02Z

0

The problem is that inside the function I declare de var every time. I put let trade out of the function

answered Nov 27, 2017 at 15:21

Pablo Malynovytch

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