I am fetching the first occurrence of a particular value in a Panda column based on its index as shown below :
first_idx = df1.loc[df1.Column1.isin(['word1','word2'])].index.tolist()[0]
This will give me the index of first occurrence of either 'word1' or 'word2'
Then I am replacing old values of the records until the determined index with new values as shown below :
df1.head(first_idx)['Column1'].replace({'10': '5'}, inplace=True)
This will replace all '10's that are present until the first_idx of the dataframe with '5's. All the remaining '10's present after the first_idx value will not be replaced.
Now I have to replace all '10's present after the first_idx value with '3's. I have tried the below by calculating the length of data frame and then subtracting it with the first_idx value.
len(df1) # This will show the actual length / total number of records of a dataframe column.
temp = (len(df1)-first_idx)-1 # This will determine the remaining count of records barring the count of records until first_idx value.
df1.tail(temp) # This will show all records that are present after the first_idx value.
df1.tail(temp)['Column1'].replace({'10': '3'}, inplace=True)
But is there any other better / efficient / simple way to achieve the same ?