function from linux shell script not execute in c program

Question

I have seen similar posts in stackoverflow and other sites but I cannot find solution to my problem.

I have the following consoleout.sh file:

#!/bin/sh

#this way works in c:
#echo "Hello World!"

#but in function does not work:
a(){
  echo "Hello World!"
}

Following C code:

#include <stdio.h>
#include <stdlib.h>

int main()
{
    system(".  consoleout.sh"); 

    system("a");
    return 0;
}

Without system("./consoleout.sh"), it works fine.

Are you sure you want to use system or code a program in C in such cases? — Basile Starynkevitch
– Basile Starynkevitch, Commented Oct 9, 2017 at 11:26

Petr Skocik · Accepted Answer · 2017-10-09 11:15:27Z

4

system() invokes a shell and waits for it to terminate. Another call to system() will create a different shell that starts from scratch.

To run your shell function, you need to do it from the shell where it was defined:

#include <stdio.h>
#include <stdlib.h>

int main()
{
    return system( ".  consoleout.sh; a" ); 
}

answered Oct 9, 2017 at 11:15

Petr Skocik

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Comments

choroba · Accepted Answer · 2017-10-09 11:13:10Z

3

Each system calls a new instance of the shell, the second one doesn't know anything about the functions defined in the first one. You can, though, call the function in the first shell:

system(". consoleout.sh ; a");

answered Oct 9, 2017 at 11:13

choroba

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