Using parameters from shell script in my Java code

Question

I have to write two scripts, one to compile my code and another one to run it. I manage to compile the code with this script:

#!/bin/bash
javac SimilaridadeP.java

And I was able to run it using this script:

#!/bin/bash
java SimilaridadeP

The problem is that I need to execute my second shell script following this command:

./execute.sh input output

Where input and output are the names of the files that I am going to use in my Java code. The problem that I am facing right now is that I don't know how I can use these both names in my Java code.

So far I managed to get both names using this code:

#!/bin/bash
in=$1
out=$2
java SimilaridadeP

But since "SimilaridadeP" is the name of my java file and it can't be called like a method with parameters I am kind of lost.

John Kugelman · Accepted Answer · 2017-10-11 20:47:24Z

3

If your java code is already reading the command-line parameters, it's just a matter of changing the bash this way:

#!/bin/bash
java SimilaridadeP "$1" "$2"

edited Oct 11, 2017 at 20:47

John Kugelman

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answered Oct 11, 2017 at 20:43

imerso

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2 Comments

Marcos Guimaraes Over a year ago

Hi, thanks for the reply! So what I have in my Java class is something similar to scanf in C. My main doubt is in how do I read the command line parameters.

imerso Over a year ago

I did not add any validation, but here is the basics: public static void main(String[] args) { String parm1 = args[0]; String parm2 = args[1]; ..... }

John Kugelman · Accepted Answer · 2017-10-11 20:47:28Z

2

This works with arbitrary number of arguments:

#!/bin/bash
java SimilaridadeP "$@"

edited Oct 11, 2017 at 20:47

John Kugelman

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answered Oct 11, 2017 at 20:44

en1010

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