var a=[1,2,3];
var b = a;
a[1]=4;
alert(a);
alert(b);
I cannot figure out why is the array B is [1,4,3] as well.
My second question is: how can I complete the function sum(a)(b), so it will return the value of a+b. For example if call sum(2)(4) it will return 6?
The reason why B gets mutated as well is that when you assign
var b = a, you are not copying the array. In javascript, arrays are objects and variables that hold object data are merely references to the object. The line a[1] = 4 changes the object both a and b are referencing.
For the second question, you want a curried version of sum. You can implement it simply as
const sum = a => (b => a + b);
Then sum(a) is the function b => a + b.
In JS var Arr1 = Arr1 does not copy it, it simply puts the reference to the array into another variable. (see @Adam Jaffe's answer)
If you are attempting to have 2 different arrays, clone the first one by slicing it at starting position.
var a=[1,2,3];
var b = a.slice(0);
a[1]=4;
console.log(a);
console.log(b);
var a =[1,2,3];
var b = [];
b = a.concat(b);
a[1]=4;
alert(a);
alert(b);
function sum(a, b){
return a + b;
}
var r = sum(2, 4);
console.log(r);
function sum(a,b)
{
return a+b;
}
var a=[1,2,3];
var b = a.slice(0);
a[1]=4;
alert(a);
alert(b);
var c=sum(2,4);
alert("c=" + c);
sum(a)(b) and not sum(a,b).