How do I list all files in a directory in Linux using bash script?

Question

I have been trying to list all the files from the "junk_dir" in a formatted style, listing them off by file name, file size and file type. Although I am not getting these printed off in a formatted way, I am getting them printed out. However, on line 10, I get an error from the command promp tsaying

./junk-skeleton.sh: line 10: [1001=: command not found

The following is my code.

#! /bin/bash 

list_junk()
{
    echo "Junk Directory"

   format="%8s%10s%10s  %-s\n"
   printf "$format" "File" "Size" "Type"
   printf "$format" "----" "----" "----"
   if [$(id -u)= "0"]; then
      dir_list="/home/student/bin/junk_dir/*"
   else
      dir_list=$HOME
   fi

  for file in $dir_list; do
      filename=$(ls -al /home/student/bin/junk_dir)
      filesize=$(wc -c /home/student/bin/junk_dir)
      filetype=$(ls --file-type /home/student/bin/junk_dir)

      printf "$format" $filename $filesize $filetype
   done
}

Also, if anybody has help formatting the printed results, I would appreciate it.

@Inian I have tried that, What I got back was ./junk-skeleton.sh: line 10: [: 1001=: unary operator expected — Jack McIvor
– Jack McIvor, Commented Oct 25, 2017 at 16:18

tink · Accepted Answer · 2019-01-24 16:15:29Z

1

You need spaces around both the brackets, and between the shell command and the equals sign.

if [ $(id -u) = "0" ]; then echo ROOT; fi

edited Jan 24, 2019 at 16:15

answered Oct 25, 2017 at 16:29

tink

15.6k5 gold badges54 silver badges58 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

How do I list all files in a directory in Linux using bash script?

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related