Merge multiple JSON into single one (Python)

Question

I am searching for a way to merge multiple JSONs into a single one. My output is in this format:

[{"Nome bollettino": "Bollettino 1"}, {"Causale": "1"}, {"Numero": "1"}]
[{"Nome bollettino": "Bollettino 2"}, {"Causale": "2"}, {"Numero": "2"}]
[{"Nome bollettino": "Bollettino 3"}, {"Causale": "3"}, {"Numero": "3"}]
[{"Nome bollettino": "Bollettino 4"}, {"Causale": "4"}, {"Numero": "4"}]
[{"Nome bollettino": "Bollettino 5"}, {"Causale": "5"}, {"Numero": "5"}]
[{"Nome bollettino": "Bollettino 6"}, {"Causale": "6"}, {"Numero": "6"}]
[{"Nome bollettino": "Bollettino 7"}, {"Causale": "7"}, {"Numero": "7"}]
[{"Nome bollettino": "Bollettino 8"}, {"Causale": "8"}, {"Numero": "8"}]
[{"Nome bollettino": "Bollettino 9"}, {"Causale": "9"}, {"Numero": "9"}]
[{"Nome bollettino": "Bollettino 10"}, {"Causale": "10"}, {"Numero": "10"}]

Every single line is a valid JSON. I a looking for a way to do it in Python, like this site do. Here you can find the code I am using to generate JSON data.

I have tried to use jsonmerge and json-merger but it's not so effective. The site above do the work perfect but I need to do it in Python.

Particularly, with jsonmerge using the syntax from the documentation, the output is only the first two values...

result = merge(bollettini, causale, numero)
print(result)

{'Nome bollettino': 'Bollettino 1', 'Causale': '1'}
{'Nome bollettino': 'Bollettino 2', 'Causale': '2'}
{'Nome bollettino': 'Bollettino 3', 'Causale': '3'}

etc...

...which are not even JSON's.

How to merge them ?

@ZdaR I don't know what do you mean. It should be a valid JSON format. Thanks — lucians
– lucians, Commented Oct 27, 2017 at 13:53
This is also a valid JSON format: [{}], what are you precisely looking for ? — ZdaR
– ZdaR, Commented Oct 27, 2017 at 13:53

Marco · Accepted Answer · 2017-10-27 14:27:05Z

4

Or like this with a 2D array output.

import json


idx = 0
count = [idx]
data = []
while idx < 10:
  idx += 1

  bollettini = {'Nome bollettino': 'Bollettino ' + str(idx) }
  causale    = {'Causale': str(idx) }
  numero =     {'Numero': str(idx)  }


  data.append([bollettini]+[causale]+[numero])

json_data = json.dumps(data)
print (json_data) #added parenthesis

answered Oct 27, 2017 at 14:27

Marco

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1 Comment

lucians Over a year ago

The answer is related to this question.

Maurice Meyer · Accepted Answer · 2017-10-27 14:26:03Z

1

... it is quite unclear what you want have, may that helps:

input = [
    [{"Nome bollettino": "Bollettino 1"}, {"Causale": "1"}, {"Numero": "1"}],
    [{"Nome bollettino": "Bollettino 2"}, {"Causale": "2"}, {"Numero": "2"}],
    [{"Nome bollettino": "Bollettino 3"}, {"Causale": "3"}, {"Numero": "3"}],
    [{"Nome bollettino": "Bollettino 4"}, {"Causale": "4"}, {"Numero": "4"}],
    [{"Nome bollettino": "Bollettino 5"}, {"Causale": "5"}, {"Numero": "5"}],
    [{"Nome bollettino": "Bollettino 6"}, {"Causale": "6"}, {"Numero": "6"}],
    [{"Nome bollettino": "Bollettino 7"}, {"Causale": "7"}, {"Numero": "7"}],
    [{"Nome bollettino": "Bollettino 8"}, {"Causale": "8"}, {"Numero": "8"}],
    [{"Nome bollettino": "Bollettino 9"}, {"Causale": "9"}, {"Numero": "9"}],
    [{"Nome bollettino": "Bollettino 10"}, {"Causale": "10"}, {"Numero": "10"}]
]

result = []
for line in input:
    result.append({k:v for x in line for (k,v) in x.items()})

result:

[{'Causale': '1', 'Nome bollettino': 'Bollettino 1', 'Numero': '1'},
 {'Causale': '2', 'Nome bollettino': 'Bollettino 2', 'Numero': '2'},
 {'Causale': '3', 'Nome bollettino': 'Bollettino 3', 'Numero': '3'},
 {'Causale': '4', 'Nome bollettino': 'Bollettino 4', 'Numero': '4'},
 {'Causale': '5', 'Nome bollettino': 'Bollettino 5', 'Numero': '5'},
 {'Causale': '6', 'Nome bollettino': 'Bollettino 6', 'Numero': '6'},
 {'Causale': '7', 'Nome bollettino': 'Bollettino 7', 'Numero': '7'},
 {'Causale': '8', 'Nome bollettino': 'Bollettino 8', 'Numero': '8'},
 {'Causale': '9', 'Nome bollettino': 'Bollettino 9', 'Numero': '9'},
 {'Causale': '10', 'Nome bollettino': 'Bollettino 10', 'Numero': '10'}]

answered Oct 27, 2017 at 14:26

Maurice Meyer

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2 Comments

lucians Over a year ago

It's not valid according to jsonlint.

Maurice Meyer Over a year ago

Yes, this is a Python object. You need to use json.dumps(result) to recieve a valid JSON string !

Keerthana Prabhakaran · Accepted Answer · 2017-10-27 15:40:36Z

1

Say you have multiple jsons as list of lists like

l = [[{"Nome bollettino": "Bollettino 1"}, {"Causale": "1"}, {"Numero": "1"}]
[{"Nome bollettino": "Bollettino 2"}, {"Causale": "2"}, {"Numero": "2"}]
[{"Nome bollettino": "Bollettino 3"}, {"Causale": "3"}, {"Numero": "3"}]
[{"Nome bollettino": "Bollettino 4"}, {"Causale": "4"}, {"Numero": "4"}]
[{"Nome bollettino": "Bollettino 5"}, {"Causale": "5"}, {"Numero": "5"}]
[{"Nome bollettino": "Bollettino 6"}, {"Causale": "6"}, {"Numero": "6"}]
[{"Nome bollettino": "Bollettino 7"}, {"Causale": "7"}, {"Numero": "7"}]
[{"Nome bollettino": "Bollettino 8"}, {"Causale": "8"}, {"Numero": "8"}]
[{"Nome bollettino": "Bollettino 9"}, {"Causale": "9"}, {"Numero": "9"}]
[{"Nome bollettino": "Bollettino 10"}, {"Causale": "10"}, {"Numero": "10"}]]

You just need to chain the lists to form a single one! Read more on itertools.chain here

>>> from itertools import chain
>>> list(chain.from_iterable(l))

after dumping your data as json Output:

[{"Nome bollettino": "Bollettino 1"}, {"Causale": "1"}, {"Numero": "1"}, {"Nome bollettino": "Bollettino 2"}, {"Causale": "2"}, {"Numero": "2"}, {"Nome bollettino": "Bollettino 3"}, {"Causale": "3"}, {"Numero": "3"}, {"Nome bollettino": "Bollettino 4"}, {"Causale": "4"}, {"Numero": "4"}, {"Nome bollettino": "Bollettino 5"}, {"Causale": "5"}, {"Numero": "5"}, {"Nome bollettino": "Bollettino 6"}, {"Causale": "6"}, {"Numero": "6"}, {"Nome bollettino": "Bollettino 7"}, {"Causale": "7"}, {"Numero": "7"}, {"Nome bollettino": "Bollettino 8"}, {"Causale": "8"}, {"Numero": "8"}, {"Nome bollettino": "Bollettino 9"}, {"Causale": "9"}, {"Numero": "9"}, {"Nome bollettino": "Bollettino 10"}, {"Causale": "10"}, {"Numero": "10"}]

edited Oct 27, 2017 at 15:40

answered Oct 27, 2017 at 14:23

Keerthana Prabhakaran

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4 Comments

lucians Over a year ago

It's not valid according to jsonlint

Keerthana Prabhakaran Over a year ago

@Link Sorry, I don't get it. Can you please explain what do you mean by not valid?

lucians Over a year ago

Paste the output to jsonlint. It will give an invalid JSON.

Keerthana Prabhakaran Over a year ago

Ah! That was because, the output that I pasted had single quotes ' instead of double quotes! " and that was because, for testing I copy pasted your input to a string and then processed it to get the lists! I've corrected the output!

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