java printf cannot print char array

Question

I am looking for a help to my code in java as I wanted to print only the uppercase of ASCII. So I made an array and run a for loop. I made an if condition to access the characters from 65 to 90, then I used this format to print the value system.

out.printf("%c : ",ch[x]).

Unfortunately I got garbage as output. here is the complete code:

           for(int x=0; x<ch.length; x++) {
            if(ch[x]>=65||ch[x]<=90) {
               System.out.printf("%c ",ch[x]);
            }
          }

Tag the question with java, research string + java + toupper, post your code to help us fix yours. — Patrick Artner
– Patrick Artner, Commented Dec 10, 2017 at 18:30
Please read minimal reproducible example and enhance your question accordingly. — GhostCat
– GhostCat, Commented Dec 10, 2017 at 18:57
@Baba, char[] ch = {'A','B','C','D','a','b'}; for(int x=0; x<ch.length; x++) { if(ch[x]>=65&&ch[x]<=90){System.out.printf("%c ",ch[x]);}} output: A B C D — dkb
– dkb, Commented Dec 10, 2017 at 19:11

Youcef LAIDANI · Accepted Answer · 2017-12-10 19:14:39Z

1

As @YCF_L said, use &&, and may, I recommend the forEach :

char[] ch = new char[]{'A', 'z', 'S', 'Z', 'H', '1', 'o'};
for (char c : ch) {

    if (c >= 65 && c <= 90) {
        System.out.printf("%c ", c);
    }
}

Outputs

A S Z H

ideone demo

edited Dec 10, 2017 at 19:14

Youcef LAIDANI

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answered Dec 10, 2017 at 19:07

SkyAnthrax94

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Comments

arst3k · Accepted Answer · 2017-12-10 19:42:56Z

0

Simply use isUpperCase() method:

for(int x=0; x<ch.length; x++) {
        if(isUpperCase(ch[x])) {
           System.out.printf("%c ",ch[x]);
        }
      }

If you don't want to use the method:

for(int x=0; x<ch.length; x++) {
        if(ch[x]>=65 && ch[x]<=90) {
           System.out.printf("%c ",ch[x]);
        }
      }

edited Dec 10, 2017 at 19:42

answered Dec 10, 2017 at 19:37

arst3k

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