Python regex replace string with pattern

Question

Regex is r'[A-z\d,\-.\ \/\n]{1,}', This regex will allow alphanumeric + some special chars.

I want to replace characters which are not allowed.

I have tried,

re.sub(r'[A-z\d,\-.\ \/\n]{1,}', ' ', 'ASGHB 3 JHDSD eyg && ^&*hdbcd v%^&*B#$%^')

Gives output as,

' && &* % &* #$% '

I want original string as output with replaced special chars (which are not allowed) with white spaces.

Expected output : ASGHB 3 JHDSD eyg ^ hdbcd v ^ B ^ How to achieve this ?

re.sub(r'[^A-z\d,\-.\ \/\n]{1,}', ' ', 'ASGHB 3 JHDSD eyg && ^&*hdbcd v%^&*B#$%^') => 'ASGHB 3 JHDSD eyg ^ hdbcd v ^ B ^' ? You should give your expected result. — Kinght 金
– Kinght 金, Commented Dec 18, 2017 at 7:36
also don't use [A-z] until or otherwise you know what it actually does. — Avinash Raj
– Avinash Raj, Commented Dec 18, 2017 at 7:42
@AvinashRaj should I use it separately ? I though [A-Za-z] and [A-z] are same, please correct me if I am wrong. — Nishant Nawarkhede
– Nishant Nawarkhede, Commented Dec 18, 2017 at 7:51
you should use that separately. Both are not same. see what are the other chars that falls within A-z range asciitable.com — Avinash Raj
– Avinash Raj, Commented Dec 18, 2017 at 7:54

Vasily Bronsky · Accepted Answer · 2017-12-18 07:44:26Z

3

You can find all about re.sub here

So about your question. You should use ^ before your set:

If the first character of the set is '^', all the characters that are not in the set will be matched. 
For example, [^5] will match any character except '5', and [^^] will match any character except '^'. 
^ has no special meaning if it’s not the first character in the set.

answered Dec 18, 2017 at 7:44

Vasily Bronsky

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