Filtering two-dimensional arrays in Javascript

Question

I have an array of integers like this:

var items = [
  [1, 1, 2, 4],
  [2, 1, 4, 6],
  [5, 6, 4, 1],
  [1, 6, 3, 1]
];

Is there a simple way to find and remove all arrays with specific values in a defined position? For example, if I want to remove all arrays with '1' on the second position, the result should be:

var items = [
  [5, 6, 4, 1],
  [1, 6, 3, 1]
];

If I remove all with '4' on the third position, the result should be:

var items = [
  [1, 1, 2, 4],
  [1, 6, 3, 1]
];

I know I can do this by looping through all elements, but this seems to take quite long when the two-dimensional array is large (>1000 arrays).

use Array.filter, combined with a function that looks up values you don't want — Abderrahmane TAHRI JOUTI
– Abderrahmane TAHRI JOUTI, Commented Dec 29, 2017 at 11:35

Suren Srapyan · Accepted Answer · 2017-12-29 11:35:18Z

11

Iterate over the items, use Array#filter function to filter those inner arrays which does not have the given value in the given position.

function filterByPosition(array, number, position) {
   return array.filter(innerArray => innerArray[position - 1] !== number);
}

const items = [
  [1, 1, 2, 4],
  [2, 1, 4, 6],
  [5, 6, 4, 1],
  [1, 6, 3, 1]
];

const newItems1 = filterByPosition(items, 1, 2);
console.log('Items1:', newItems1);

const newItems2 = filterByPosition(items, 4, 3);
console.log('Items2:', newItems2);

answered Dec 29, 2017 at 11:35

Suren Srapyan

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