How I can validate this pattern using regex

Question

I try to write a regex to validate a pattern, but I have some problems. This the pattern that I should get and validate using a regex

XXXX
XXXX-XXXX
XXXX-XXXX-XXXX-XXXX-XXXX

Every X is an Int number [0-9]

I'm trying with this :

[0-9]{4}(-?[0-9]{4})?

but it gives me this pattern :

**4586-4584**-**5588-5558**-**5888-5545**

Any idea how to fix this problem? Thanks in advance!

Do you want to match 1, 2 or 5 appearances of XXXX (with hyphens, of course)? — GalAbra
– GalAbra, Commented Jan 18, 2018 at 10:21
@GalAbra I want to valide values like 5125 or 5125-3658 or 5885-9687-2545 the number of appearences of XXXX is 1 to 6 — e2rabi
– e2rabi, Commented Jan 18, 2018 at 10:23
@GalAbra the max character of this pattern should not be more than 35 "-" included — e2rabi
– e2rabi, Commented Jan 18, 2018 at 10:26

The fourth bird · Accepted Answer · 2018-01-19 08:42:45Z

1

Your pattern [0-9]{4}(-?[0-9]{4})? uses an optional hyphen -? and an optional group (-?[0-9]{4}).

The optional hyphen -? will allow for example 8 digits in a row (4 digits followed by 4 digits).

The optional group will allow only 0 or 1 occurances so XXXX-XXXX-XXXX will not match.

Not using anchors for the beginning and the end of the line, will match 3333-3333 in 333-3333-3333.

You could update your regex to ^[0-9]{4}(-[0-9]{4})*$, or with \d: ^\d{4}(?:-\d{4})*$

Explanation

From the beginning of the string ^
4 digits \d{4}
A non capturing group to match a hyphen and 4 digits (?:-\d{4})
Repeat that group zero or more times *
The end of the string $

edited Jan 19, 2018 at 8:42

answered Jan 19, 2018 at 8:31

The fourth bird

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Comments

Shen Yudong · Accepted Answer · 2018-01-18 11:00:59Z

1

[0-9]{4}(-[0-9]{4})*

try this one, you need -, can't add ? ahead it. add * instead of ?, because may have more than one

(?<![0-9\-])[0-9]{4}(-[0-9]{4})*(?![0-9\-])

this one will not match 1234-5667-78961234

edited Jan 18, 2018 at 11:00

answered Jan 18, 2018 at 10:24

Shen Yudong

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e2rabi Over a year ago

This regex allows values likes 5858-8589-55858888

GalAbra · Accepted Answer · 2018-01-18 11:04:25Z

1

^(\d{4})(-(\d{4})){0,5}$

If I understood correctly, you're looking for a pattern of XXXX (so every X is a digit) that appears 1 to 6 times, with hyphens in between.

Hence, the first 4 digits are mandatory, and then it's possible to have 1 to 5 appearances of -XXXX.

Note the ^ and the $, that make sure the regex doesn't match only a part of a string.

edited Jan 18, 2018 at 11:04

answered Jan 18, 2018 at 10:34

GalAbra

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user2342558 · Accepted Answer · 2018-01-18 10:26:57Z

0

Try with this pattern:

    (\b([0-9]){4}\b)|(\b([0-9]){4}\-([0-9]){4}\b)|(\b([0-9]){4}\-([0-9]){4}\-([0-9]){4}\b)|(\b([0-9]){4}\-([0-9]){4}\-([0-9]){4}\-([0-9]){4}\b)

Demo

edited Jan 18, 2018 at 10:26

answered Jan 18, 2018 at 10:16

user2342558

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2 Comments

e2rabi Over a year ago

Thanks I try it it not working this regex allow values like 4588-5585-55546928

user2342558 Over a year ago

Upated. Maybe a shorted version but that one may work.

L3R04 · Accepted Answer · 2018-01-18 10:26:34Z

-2

This should do it. Only tried it using C# though.

[0-9]{4}-[0-9]{4}-[0-9]{4}-[0-9]{4}-[0-9]{4}

answered Jan 18, 2018 at 10:26

L3R04

1

1 Comment

Fabian S. Over a year ago

This does not match 1234 or 1234-5678

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