Create a calculations operator in python [duplicate]

Question

So I am developing a class for vectorial calculations, and I overwrote the __mul__(self, b) function to do a Scalarproduct. Now whenever I write A * B it calculates as I want it to. So I would like to do the same with an x for the Crossproduct. Sadly there is no default x operator in python, it would probably just annoy you. But is there a way to create your own operator which ONLY works for my own class, but can otherwise be used in a code aswell (as a variable definition I mean)? Or maybe define *** as an operator?

In brief: No, you cannot define your own operators in Python. — DYZ
– DYZ, Commented Jan 25, 2018 at 6:37
As DYZ's pointer question suggests, you may want to check out this hacky approach: code.activestate.com/recipes/384122-infix-operators — WillMonge
– WillMonge, Commented Jan 25, 2018 at 6:53
In recent versions of Python you could override the __matmul__ method, which is associated with the @ operator. It's supposed to be for matrix multiplication, but that's not a hard & fast rule. — PM 2Ring
– PM 2Ring, Commented Jan 25, 2018 at 8:35

englealuze · Accepted Answer · 2018-01-25 08:39:47Z

0

Instead of just define an operator, you can write your own interpreter for your own language inside python. Basically, you need to create 4 modules

parser
environment
eval
repl

Then you can program with your own language within python.

read Peter Novig's article for a detailed example of a python LISP interpreter

edited Jan 25, 2018 at 8:39

answered Jan 25, 2018 at 8:06

englealuze

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