Join string to array with Regex

Question

Given this string:

"ManagerID='26a20e0e-23ba-4133-8bf4-e56f13115902' OR ManagerID='c86eede4-fdb4-45a8-88cf-4041c9d7a327'"

How can I transform it to this array:

["26a20e0e-23ba-4133-8bf4-e56f13115902", "c86eede4-fdb4-45a8-88cf-4041c9d7a327"]

Basically pulling out the OR and joining it. I can't seem to figure this one out.

str.scan(/(?<=ManagerID=').*?(?=')/)

Sagar Pandya
– Sagar Pandya

2018-02-13 21:17:40 +00:00
Commented Feb 13, 2018 at 21:17 — Sagar Pandya
– Sagar Pandya, Commented Feb 13, 2018 at 21:17

Bartosz Pietraszko · Accepted Answer · 2018-02-13 21:00:12Z

1

string = "ManagerID='26a20e0e-23ba-4133-8bf4-e56f13115902' OR ManagerID='c86eede4-fdb4-45a8-88cf-4041c9d7a327'"

string.split(" OR ").map{ |x| x.gsub(/(^ManagerID='|'$)/, "") }

answered Feb 13, 2018 at 21:00

Bartosz Pietraszko

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Shobi · Accepted Answer · 2018-02-13 20:57:58Z

ruby noob here, any way

 "ManagerID='26a20e0e-23ba-4133-8bf4-e56f13115902' OR
 ManagerID='c86eede4-fdb4-45a8-88cf-4041c9d7a327'".gsub(" OR ",'')

would produce =>"ManagerID='26a20e0e-23ba-4133-8bf4-e56f13115902' ManagerID='c86eede4-fdb4-45a8-88cf-4041c9d7a327'"

then split it by ManagerID=

    "ManagerID='26a20e0e-23ba-4133-8bf4-e56f13115902'
 ManagerID='c86eede4-fdb4-45a8-88cf-4041c9d7a327'".split("ManagerID=")

would produce => ['26a20e0e-23ba-4133-8bf4-e56f13115902', '26a20e0e-23ba-4133-8bf4-e56f13115902']

then simply join them by coma

['26a20e0e-23ba-4133-8bf4-e56f13115902', '26a20e0e-23ba-4133-8bf4-e56f13115902'].join(',')

this should give you the expected result, basically you can chain these operations into one statement, if my knowledge is correct, below code would give you the result.

 "ManagerID='26a20e0e-23ba-4133-8bf4-e56f13115902' OR ManagerID='c86eede4-fdb4-45a8-88cf-4041c9d7a327'".gsub(" OR ",'').split("ManagerID=").join(',')

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