filter String with empty String in if statement, iOS

Question

I'm working on a custom keyboard. I'm having trouble filtering Strings Array. I want to filter the array only in if statement, I have an array with letters and empty String's. I want to filter Array only in if statement because I want to remove last character, not empty String.

Here is my code:

keyboardKeyStr = ["h", "e", "l", "l", "o", " ", "", "t", "h", "i", "s", "", "i", "s", " ", "m", "y", " ", "", "a", "r", "r", "a", "y", " "]

if range.length == 1 && text.count == 0 {
    print("Delete Button")

    let emptyStr: String? = ""
    keyboardKeyStr = keyboardKeyStr.filter {$0 != emptyStr}
    keyboardKeyStr.removeLast()
    keyboardKeyArr.append(keyboardView.deleteBtn)
    self.keyboardKeyStr.append("")
}

Your question is a bit confusing. You should add an example array and the expected result. By the way you can replace text.count == 0 with text.isEmpty and filter {$0 != emptyStr} with filter {!$0.isEmpty} and delete the let emptyStr line. And why do you declare emptyStr as an optional but assign an non-optional value?? Don't annotate worse types than the compiler can infer. — vadian
– vadian, Commented Mar 1, 2018 at 15:52
@SandrikaJanjghava You did not include the expected result. (What result are you receiving, and what did you want it to be, and why?) — Rob Napier
– Rob Napier, Commented Mar 1, 2018 at 18:43

Tiago Couto · Accepted Answer · 2018-03-01 19:19:12Z

1

Try this keyboardKeyStr = keyboardKeyStr.filter{ $0 != "" && $0 != " "}

answered Mar 1, 2018 at 19:19

Tiago Couto

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1 Comment

Sandrika Janjghava Over a year ago

filter is finding and removing, deleting. I found filterMap and that does great work

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