I have a string: a = '*1357*0123456789012345678901234567890123456789*2468*'
I want to find a value between 1357 and 2468 which is 0123456789012345678901234567890123456789.
I want to use regex or easier method to extract the value.
I tried re.findall(r'1357\.(.*?)2468', a), but I don't know where I'm doing wrong.
You have a couple of problems here:
. after 1357, which means a literal ., which isn't what you meant to have* characters (which do need to be escaped, of course).To make a long story short:
re.findall(r'1357\*(.*?)\*2468', a)
If you want a slightly more general or flexible method, you can use this:
re.findall(r'\*\d+\*(\d+)\*\d+\*',a)
Which gives you the same output:
['0123456789012345678901234567890123456789']
But the advantage is that it gives you the value between any set of numeric values that are surrounded by the *. For instance, this would work for your string, but also for the string a = *0101*0123456789012345678901234567890123456789*0*, etc...
