php shows empty array but ajax shows the data

Question

I am trying to use the data that AJAX sends in PHP but for some reason says that the array is empty I also don't get any errors from PHP or in my console. the console.log(data) shows the array with with the values of the selects. After the PHP there is HTML where the script.js is.console.log

index.php

 <?php
    error_reporting(-1);
    $value1 = "";
    $value2 = "";
    print_r($_POST); 
    if (isset($_POST['date']) && isset($_POST['date'])) {
        if (isset($_POST['date'])) {
            echo "Yes, mail is set";
            $value1 = $_POST['date'];
            $value2 = $_POST['quantity'];
        } else {
            echo "No, mail is not set";
        }
        exit;
    }
    echo $value1; 
    echo $value2;
    $canmakereservation = "https://www.planyo.com/rest/?method=can_make_reservation&api_key=YOURKEY&resource_id=110556&start_time=2018-04-25 09:00&end_time=2018-04-25 12:00&quantity=5";
    $cleancanmakereservation = preg_replace("/ /", "%20", $canmakereservation);
    $reservationavailable = file_get_contents("$cleancanmakereservation");
    $reservationAvailable = json_decode($reservationavailable, true);
    // echo "$cleancanmakereservation";
    // var_dump($reservationAvailable);
 ?>

script.js

$(document).ready(function(){

var date = "date";
var begin = "begin";
var eind = "eind";
var aantal = "aantal";


$('#datum').change(function() {
  date = $("#datum").val();
  console.log(date);
});
$('#beginTijd').change(function(){
    begin =( $(this).val() ); 
    console.log(begin);      
});
$('#Tijdsduur').change(function(){
    eind =( $(this).val() ); 
    console.log(eind);      
});
$('#aantalSloepen').change(function() {
aantal = ($(this).val());
console.log(aantal);
  $.ajax({
      type: "POST",
      url: "index.php",
      data: {
          date: begin,
          quantity: aantal
      },
      success: function(data) {
          alert(data);
          console.log(data);
      }
  });
});
});

Small Point if (isset($_POST['date']) && isset($_POST['date'])) { you should probably be testing $_POST['quantity'] rather than testing date twice — RiggsFolly
– RiggsFolly, Commented Mar 28, 2018 at 9:47
What do you mean, shows empty? I can clearly see the output of the var_dump() in your console output. — jeroen
– jeroen, Commented Mar 28, 2018 at 9:47
I can see values of date and quantity from your console image — Pankaj Makwana
– Pankaj Makwana, Commented Mar 28, 2018 at 9:48
i think if php doesn't return a json. echo. and return are equivalent. So it cannot be faulted with string ! except other variable type — An Pham Karion Co.Ltd
– An Pham Karion Co.Ltd, Commented Mar 28, 2018 at 10:03

An Pham Karion Co.Ltd · Accepted Answer · 2018-03-28 11:15:34Z

2

First! There are duplicate conditions isset($_POST['date']) (3 times) in your code:

 if (isset($_POST['date']) && isset($_POST['date'])) {
        if (isset($_POST['date'])) {
            echo "Yes, mail is set";
            $value1 = $_POST['date'];
            $value2 = $_POST['quantity'];
        } else {
            echo "No, mail is not set";
        }
        exit;
    }

Second! You should remove exit; and try again!

Third: You should check your variable type, if your $value1 and $value2 is not a string, numeric. echo is false. try with return

EDIT:

Try this, it worked for me! the .php destination:

$value1 = "";
$value2 = "";
if (isset($_POST['date']) && isset($_POST['quantity'])) {

        echo "Yes, mail is set";
        $value1 = $_POST['date'];
        $value2 = $_POST['quantity'];
    }
    else {
        echo "No, mail is not set";
}
echo $value1;
echo $value2;

The ajax:

The result

edited Mar 28, 2018 at 11:15

answered Mar 28, 2018 at 9:50

An Pham Karion Co.Ltd

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14 Comments

berto Over a year ago

I removed exit; and changed the secods isset($_POST['date']) to quantity. but don't really understand what you mean by your third point.

An Pham Karion Co.Ltd Over a year ago

@berto echo cannot be used with an object (example date time...) or array, you know? so i advise you to use return instead of echo :)

An Pham Karion Co.Ltd Over a year ago

if echo in your .php is wrong, your ajax result will be nothing

An Pham Karion Co.Ltd Over a year ago

you should use var_dump() to check your variables before return it !

berto Over a year ago

I have changed the print_r($_POST); to var_dump($_POST) and it says array (size=0) empty

|

benmccallum · Accepted Answer · 2018-03-28 10:17:11Z

0

Check the ContentType header in the AJAX request. It could be that it is being sent as JSON and PHP doesn't deserializer that into the $_POST array. It may need to be sent as serialized form data, like in this example.

In my experience (albeit in .NET), if data isn't being picked out of the request by the server it's usually that the ContentType header isn't set correctly for how you're passing the data so the server doesn't understand how to pull it out.

Edit: You can control this by setting contentType property in options object passed to $.ajax, the default is apparently 'application/x-www-form-urlencoded; charset=UTF-8' and when you pass an object to the data property, according to the processData property, the default behaviour is to serialize this into a query string, fitting the default contentType. Source: jQuery docs.

So my mistake, looks like that should all be matching up, though I do usually like to be explicit with specifying these properties to avoid any confusion.

edited Mar 28, 2018 at 10:17

answered Mar 28, 2018 at 9:50

benmccallum

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4 Comments

An Pham Karion Co.Ltd Over a year ago

I think with his code ! It only send a Post request. doesn't it?

benmccallum Over a year ago

He's definitely sending a POST request, but the ContentType header that goes along with it describes to the server how the data is being sent in that request (e.g. as JSON, form-encoded, etc.). You can control this by setting contentType in options object passed to $.ajax, the default is 'application/x-www-form-urlencoded; charset=UTF-8' which may not align with the raw object passed in the data property.

An Pham Karion Co.Ltd Over a year ago

i think his variables is not string or numeric. it may be an object ! so echo false. xD

berto Over a year ago

I set the contentType to the default 'application/x-www-form-urlencoded; charset=UTF-8' but it does not make a difference.

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