Access elements of json in an Array in jquery

Question

I am trying to access an data inside an Array in Jquery but I am unable to do so. The data is getting received in success function in Ajax. My array looks like this:

[{"id":"22","name":"Ignis","color":"white","manufacturer":"Suzuki","manufacturing_year":"2017"}]

I am trying to access it like:

var obj = data;
var name = obj[0].name;
alert(name);

its getting me undefined but When I store the same received value in store it in variable like below it gives me result:

var mydata = [{"id":"22","name":"Ignis","color":"white","manufacturer":"Suzuki","manufacturing_year":"2017"}];
var obj = mydata;
var name = obj[0].name;
alert(name);

I need every value of the json to be stored in variables named after there respective keys. Please let me know how can I handle this data. Thanks.

Why when you already have simple access using the property keys? This sounds like an XY problem — charlietfl
– charlietfl, Commented Apr 8, 2018 at 19:11
@vikesh you can get a clue from here stackoverflow.com/questions/49606162/… — Abdul Qayyum
– Abdul Qayyum, Commented Apr 8, 2018 at 19:13
@vikesh could you change your question and write your expected result? — Abdul Qayyum
– Abdul Qayyum, Commented Apr 8, 2018 at 19:14
What you're trying to do makes absolutely no sense, and there is 100% a better way to do it. Try to create a good question that explains what (code) brought you into the situation. — baao
– baao, Commented Apr 8, 2018 at 19:14

Ankit Agarwal · Accepted Answer · 2018-04-09 08:03:09Z

0

I think you're asking for something like this

var  mydata='[{"id":"22","name":"Ignis","color":"white","manufacturer":"Suzuki","manufacturing_year":"2017"} ]';
var mydataobj= JSON.parse(mydata);
var name= mydataobj[0].name;
var id= mydataobj[0].id;
var color=mydata[0].color;

It goes same for all other values

edited Apr 9, 2018 at 8:03

Ankit Agarwal

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answered Apr 8, 2018 at 19:34

pyrogrammer

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3 Comments

vikesh Over a year ago

I have used JSON.parse(data); then tried to access the variable but it still giving me undefined.

vikesh Over a year ago

Yeah I did that too. It gives me this error: json_decode is not defined

pyrogrammer Over a year ago

@vikesh I guess this updated answer will solve problem

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