Bash awk: parsing variable string into another variable? [duplicate]

Question

I would like to extract all the values contained in $line and put them in variables var1, var2,... varn. I did use this previously to extract the vars from file (in.txt)

var1=$(awk  '{print  $1}' < in.txt)
var2=$(awk  '{print  $2}' < in.txt)
....
varn=$(awk  '{print  $n}' < in.txt)

How should I change my awk call so as to use $line instead of in.txt? I tried these for example

echo $line | var2=$(awk '{print  $2}')

or

var2=$(echo $line | awk '{print  $2}')

but without success...

========== DETAIL==============

----- calling file:

 .....
    name=Matrix
    line=$(sed  -n '/^\[T\]/ {n;p}' in.txt)
    echo 'line: ' $line
    L1=$(./procline_matrix_vars.sh $line 30 $name)
    echo 'L1: ' $L1

------- rocline_matrix_vars.sh:

#!/bin/bash

line=$1
choice=$2

var1=$(echo $line | awk '{print $1}')
var2=$(echo $line | awk '{print $2}')
var3=$(echo $line | awk '{print $3}')
var4=$(echo $line | awk '{print $4}')


if [ $choice == 30 ]; then
    L1=$(printf '\n\n\n%s = [ %s %s %s %s \n' "$3" "$var1" "$var2" "$var3" "$var4") 
fi

echo  "${L1%.}"

var2=$(echo $line | awk '{print $2}') should work, is it not giving you any values when you do echo "var2"? — RavinderSingh13
– RavinderSingh13, Commented Apr 9, 2018 at 14:21
not sure why you need awk.. also, variable quoting may be an issue.. could you change $line to "$line" in calling file and just to make it robust, double quote other places and other variables too... you can also use shellcheck.net to catch such issues — Sundeep
– Sundeep, Commented Apr 9, 2018 at 15:08

kyodev · Accepted Answer · 2018-04-09 14:22:29Z

1

a possible way:

line="aaa bbb ccc"

var=( $line )

echo "${var[1]}"
echo "my array has ${#var[@]} elements"

output

bbb
my array has 3 elements

maybe shortcut

var=( $( awk '{print $1, $2, $10}' file ) )

answered Apr 9, 2018 at 14:22

kyodev

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