Sorting Array using JavaScript/jQuery

Question

I have an array as shown below:

var fruits = ['0-2','1-1','12-2','14-2','2-3','21-1','4-1'];

It gives me output like this:

0-2,1-1,12-2,14-2,2-3,21-1,4-1.

I want to sort this array and get output as:

0-2,1-1,2-3,4-1,12-2,14-2,21-1 using JavaScript/jQuery.

I tired using fruits.sort(); but that does not work, any suggestions?

Great. What have you tried so far? Post your code if you want debugging help. — CertainPerformance
– CertainPerformance, Commented Apr 24, 2018 at 4:18
Use Array.prototype.sort(developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…) with passing function for compare — Isitea
– Isitea, Commented Apr 24, 2018 at 4:20

Mamun · Accepted Answer · 2018-04-24 15:25:50Z

5

You have to format the input (by removing the hyphen) before comparison to get the expected result:

var fruits = ['0-2','1-1','12-2','14-2','2-3','21-1','4-1'];

fruits.sort(function(a, b){
  a = a.replace('-', '')
  b = b.replace('-', '');
  return a - b;
});
console.log(fruits)

edited Apr 24, 2018 at 15:25

answered Apr 24, 2018 at 4:21

Mamun

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Eddie · Accepted Answer · 2018-04-24 04:21:58Z

3

You have to pass a compareFunction and split() the string and compare the first element of the array

var fruits = ['0-2', '1-1', '12-2', '14-2', '2-3', '21-1', '4-1'];

fruits.sort((a, b) => a.split('-')[0] - b.split('-')[0]);

console.log(fruits);

Doc: sort()

answered Apr 24, 2018 at 4:21

Eddie

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