Java print a pattern with nested for loop

Question

I am struggling to build an algorithm that would print the much needed pattern. The code is the following:

public static void printPatternH(int size)
{
    for (int row = 1; row <= size; row++)
    {
        for (int col = 1; col <= 2*size; col++)
        {
            if (col > size + row - 1) {
                continue;
            }
            if (col <= size) {
                System.out.print((row + col >= size + 1 ? (row + col)%size : " ") + " ");
            }
            else {
                System.out.print((row + col >= size + 1 ? (row + size)%col : " ") + " ");
            }                
        }
        System.out.println();
    }
}

The result is:

I understand that if size is 9 the last number in the middle will be 0 as (row + size)%col = 0, however I couldn't figure out a way to modify it without changing the rest of the values.

@AgelKoh yes, exactly, the solution from saka1029 fulfilled my query :) thanks — winnergo
– winnergo, Commented May 9, 2018 at 9:34

user4910279 · Accepted Answer · 2018-05-09 08:58:41Z

3

Change

(row + col)%size

to

(row + col - 1) % size + 1

answered May 9, 2018 at 8:58

user4910279

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Comments

Nimantha · Accepted Answer · 2021-10-31 10:11:55Z

1

You can check for the "0" and replace it before printing it out:

 if (col <= size) {
     //print left hand side
     int remainder =  (row + col) % size;
     if (remainder == 0) remainder = size; //replace the "0" with size here.
     System.out.print((row + col >= size + 1 ? remainder : " ") + " ");
} else {
     //print right hand side
     System.out.print((row + col >= size + 1 ? (row + size) % col : " ") + " ");
}

It will give this output:

                1 
              1 2 1 
            1 2 3 2 1 
          1 2 3 4 3 2 1 
        1 2 3 4 5 4 3 2 1 
      1 2 3 4 5 6 5 4 3 2 1 
    1 2 3 4 5 6 7 6 5 4 3 2 1 
  1 2 3 4 5 6 7 8 7 6 5 4 3 2 1 
1 2 3 4 5 6 7 8 9 8 7 6 5 4 3 2 1

edited Oct 31, 2021 at 10:11

Nimantha

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answered May 9, 2018 at 8:54

Angel Koh

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Comments

Nimantha · Accepted Answer · 2021-10-31 10:11:25Z

0

public class Testb 
{
    int item = 9;
    int limit = 5;
    int half = item/2;
    public static void main(String[] args) 
    {
        //System.out.println("Hello World!");
        for(int i=0;i<limit;i++){
          
           for(int j=0;j<half;j++){
              
              if(j<(half-i)){
               
                 print(" ");
               
              }else{
              
                 print(j-(half-i))
              
              }          
           }
           
           print(i);

           for(int k=half;k<(half+i);k++){
           
               print((half+i)-(k+1));
           
           }

           println();
        }
    }
}

output:

          0
        0 1 0
      0 1 2 1 0
    0 1 2 3 2 1 0
  0 1 2 3 4 3 2 1 0

edited Oct 31, 2021 at 10:11

Nimantha

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answered Nov 30, 2019 at 14:40

gpuser

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Comments

Nimantha · Accepted Answer · 2021-10-31 10:10:50Z

-1

 int rowCount = 1;

    System.out.println("Here Is Your Pyramid");

    //Implementing the logic

    for (int i = noOfRows; i > 0; i--)
    {
        //Printing i*2 spaces at the beginning of each row

        for (int j = 1; j <= i*2; j++)
        {
            System.out.print(" ");
        }

        //Printing j value where j value will be from 1 to rowCount

        for (int j = 1; j <= rowCount; j++)             
        {
            System.out.print(j+" ");
        }

        //Printing j value where j value will be from rowCount-1 to 1
         
        for (int j = rowCount-1; j >= 1; j--)
        {                 
            System.out.print(j+" ");             
        }                          
         
        System.out.println();

        //Incrementing the rowCount

        rowCount++;
    }

edited Oct 31, 2021 at 10:10

Nimantha

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answered May 9, 2018 at 8:56

pravin maske

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1 Comment

azro Over a year ago

He does not ask a fully way different of his one, but to fix his one, he won't learn it he just use another way.

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