how to output the array in php?

Question

Array
(
   [menu-162] => Array
    (
        [attributes] => Array
            (
                [title] => example1
            )

        [href] => node/13
        [title] => test1
    )

[menu-219] => Array
    (
        [attributes] => Array
            (
                [title] => example2
            )

        [href] => node/30
        [title] => test2
    )

)

If I assign the above array to a variable named $hello, now, I want to use a loop only output the menu-162, menu-219.

If I want to only output the attributes title value, if I only want to output the href's value.

How do I write these loops?

This is really basic stuff. Have you tried anything? Looked at the foreach documentation? Tried to loop through the array and print_r on each iteration to see what you can work with? — deceze
– deceze ♦, Commented Feb 23, 2011 at 5:14
please add an example of what you would expect the output to be look like — Stephen
– Stephen, Commented Feb 23, 2011 at 5:15

JohnP · Accepted Answer · 2011-02-23 05:14:19Z

4

foreach ($hello as $item) {
  $attr = $item['attributes']['title'];
  $href = $item['href'];
  echo "attr is {$attr}";
  echo "href is {$href}";
}

That should output the attr and href.

answered Feb 23, 2011 at 5:14

JohnP

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Comments

Russell Dias · Accepted Answer · 2011-02-23 05:15:53Z

0

You can access titles value within the attributes array like so: $hello['menu-162']['attributes']['title'] and for any other 'menu' you can substitute menu-162 with the appropriate menu-number combination. As for the href a simple $hello['menu-162']['href']

As for a loop to access both the values a simple foreach should suffice:

foreach($hello as $value) {
    echo $value['attributes']['title'];
    echo $value['href'];
}

answered Feb 23, 2011 at 5:15

Russell Dias

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Comments

corrodedmonkee · Accepted Answer · 2011-02-23 09:24:37Z

0

foreach($hello as $key => $value) {
    switch($key) {
        case 'menu-162':
        case 'menu-219':
            if($value['href'] && $value['attribute'] && $value['attribute']['title']) {
                $href = $value['href'];
                $attr = $value['attribute']['title'];
            }
        break;
        default:
            continue; //didn't find it
        break;
    }
}

If you do not need the specific menu finding, remove the switch statement. If you do need the specific ids using this is the more scalable solution, and is faster than a nested if. It will also not create notices for variables that don't exist and will only return if both attribute title, and href exist.

answered Feb 23, 2011 at 9:24

corrodedmonkee

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