Selecting inner text when using find element by css selector python, selenium and create a loop

Question

im trying to get all link text from a tag p and with a specific class. Then create a loop to find all other similar elements.

how it looks

so far i am using this : the value i want is in

    <div class='some other class'>
     <p class='machine-name install-info-entry x-hidden-focus'> text i want 
     </p> ==$0

    installations = browser.find_elements_by_css_selector('p.machine-name.install-info-entry.x-hidden-focus')

any help is appreciated. thanks.

the text i want is after the tag <p and after the second class ' machine-name....'> text i want. — Rob
– Rob, Commented Aug 3, 2018 at 17:07

cruisepandey · Accepted Answer · 2018-08-03 17:15:54Z

1

You can just use .text

installations = browser.find_elements_by_css_selector('p.machine-name.install-info-entry.x-hidden-focus') 

for installation in installations: 
  print(installation.text)

Note that installations is a list of web elements, whereas installation is just a web element from the list.

UPDATE1:

If you want to extract the attribute from a web element, then you can follow this code:

print(installation.get_attribute("attribute name"))

You should pass your desired attribute name in get_attribute method.

You can read innerHTML attribute to get source of the content of the element or outerHTML for source with the current element.

installation.get_attribute('innerHTML')

Hope this will be helpful.

edited Aug 3, 2018 at 17:15

answered Aug 3, 2018 at 16:52

cruisepandey

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3 Comments

Rob Over a year ago

thanks for the answer, i gave this a try and no errors but the file is not generated and if i create it, nothing is written to it.

cruisepandey Over a year ago

Which file you are talking about ?

Rob Over a year ago

oh my bad its not a file, its the attribute from installation.

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