I'm trying to loop through the first 5 items of an array that contain a specific value.
The code below causes an infinite loop.
$i = 0;
while ($i < 5):
if ($counselor[$i]->state == $state || !$state):
// do stuff
$i++;
endif;
endwhile;
Essentially I want to end the loop after the if statement has run 5 times.
While others have explained why your solution currently does not work, and some ways around it, the best alternative is to loop the entire array until you find 5 matches - by using a foreach-loop instead.
By using an foreach-loop, you will never run into issues if the array has less than 5 matching elements (if it has less than 5 matching elements, it will never break).
$i = 0;
// Loop the array
foreach ($counselor as $k=>$v) {
// Check if there is a match
if ($v->state == $state || !$state) {
// Do whatever if a match here
$i++;
}
// If we have found 5 matches, break out of the loop!
if ($i == 5) {
break;
}
}
You can now check how big $i is, and if less than 5, you found less than 5 matches. If it's exactly 5, you found your matches, and ended the loop.
If the if statement is not met, then you will only stay checking the $counselor[0]->state.
You need a separate counter for when the if statement is met.
$i = 0;
$containsCount = 0;
while ($containsCount < 5 || !isset($counselor[$i])):
if ($counselor[$i]->state == $state || !$state):
// do stuff
++$containsCount;
endif;
++$i;
endwhile;
I've also added a bounds check by checking if the $counselor[$i] is null. (could also check $i < $arrayLength)
If your if statement is false the first time ($i = 0) it will never match...since $i always will be 0. The same goes for $i = 1, 2, 3 or 4. If any of those are false, the loop will be stuck. $i will never increase. You need another solution.
You increment $i only when the if statement returns true. If you take your $i++; out of the if statement the loop will always run exactly 5 times.
$i = 0;
while($i < 5):
if($counselor[$i]->state == $state || !$state):
// do stuff
endif;
$i++;
endwhile;
$counselor array and then have a break after 5 successful if statements or otherwise it will stop once you reach the end of the $counselor array.You have to exit $i++ of your if condition :
$i = 0;
while($i < 5):
if($counselor[$i]->state == $state || !$state):
// do stuff
endif;
$i++;
endwhile;
if condition. You have to limit the while to avoid infinite loop. Are you sure then you r if condition is not always false?if the if() condition is not met 5 times, it will be infinite as the while() condition will never be met. Instead of while statement, use a loop that matches the length of the array and it will end then when it reaches the end of the array.
Maybe you can try altering your if statement a bit like this :
$i = 0;
while($i < 5):
if($counselor[$i++]->state == $state || !$state):
// do stuff
endif;
endwhile;
var_dump($counselor[$i]->state,$state)without using if-else block inside the loop for let saywhile(count($counselor))