I've an array, for example:
Array = [100]*100
Then I want to do this:
Array[0:10] = 1
The Array should look like this:
Array = [1,1,1,1,1,1,1,1,1,1,100,100....,100]
But Python says No and gives me
Array[0:10] = 1 can only assign an iterable
What does it want and how can I fix it?
You can use array[0:10] = [1] * 10, you just need to make an array of the size of the slice you are replacing.
Another way is to turn your list into a numpy array, and numpy will broadcast your value to the whole part of the array:
import numpy as np
a = np.array([100]*100)
a[0:10] = 1
print(a)
# array([ 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 100, 100, 100,
# 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100,
# ...
# ])
I'll give you an example with list:
L = [0 for k in range(100)] # List of 0
L[10:20] = [1 for k in range(10)]
# Output:
L = [0, ..., 0, 1, 1, ..., 1, 0, ..., 0]
You need to give a list as well to replace N values.
[1] * 10. However, indeed, it's not as efficient.the type of operands in both side should be same in this case
Array[0:10]=[1]*10
I suggest to write it as:
array = [100 for _ in range(100)]
for i in range(10):
array[i] = 1
print(array)
output: [1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100, 100]
Array[0:10] = [1]*10