Pass command line arguments to python script that is called through unix executable

Question

I have a file named "uscf" in /usr/local/bin:

#! /bin/sh
python3 ~/Desktop/path/to/uscf.py

I have already chmod +x this file so that I can run it from my terminal with the command "uscf". How can I run this with command line arguments so that the arguments are accessible through sys.argv in uscf.py?

EDIT: Added below example for clarification:

The uscf.py file:

import sys
if len(sys.argv) > 1:
print(sys.argv)

Running it from the command line:

Abraham$ uscf these are arguments

Expected output:

these are arguments

did you mean to say that you want to take input from the python script, here uscf.py ? — user2906838
– user2906838, Commented Aug 17, 2018 at 4:09
Are you talking about argparse? docs.python.org/3/library/argparse.html — MatrixTXT
– MatrixTXT, Commented Aug 17, 2018 at 4:10
No, I want to run the unix executable through the command line and give it some arguments — Abraham
– Abraham, Commented Aug 17, 2018 at 4:10
I would make it #!/usr/bin/python and have setup.py have scripts section to call your python executable with argparse or argv — bison
– bison, Commented Aug 17, 2018 at 4:12
See jordanm's answer, it is what I was looking for. I also added an edit for clarification — Abraham
– Abraham, Commented Aug 17, 2018 at 4:19

jordanm · Accepted Answer · 2018-08-17 14:01:47Z

2

In sh the "$@" variable contains all the positional arguments passed to the script. You can use that to pass it to your python script:

#!/bin/sh
python3 $HOME/Desktop/path/to/uscf.py "$@"

edited Aug 17, 2018 at 14:01

answered Aug 17, 2018 at 4:11

jordanm

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1 Comment

tripleee Over a year ago

You cannot use ~ for $HOME in sh scripts. See also Difference between sh and bash

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