How to catch error code from one shell script into another shell script

Question

The thing is : I have one python file
I am executing it using a shell script named run.sh
content of run.sh

python test.py

and in python file I am testing for something and if it is not matching i am exiting using sys.exit(1). I am able to catch this in run.sh using $? But The problem is there is a master shell script ,

master.sh

and run.sh is called from master.sh .
Mater.sh calls multiple shell script from inside. i.e

sh run.sh
sh test.sh

I want to ensure that if run.sh fails , i.e if python file exits with sys.exit(1) then it is catched in master.sh and it doesn't run the next shell script i.e it should then not run the test.sh

Mayank Porwal · Accepted Answer · 2018-10-16 17:54:10Z

1

You can do the same thing you did for run.sh, catch the return_code

in master.sh

sh run.sh
if [ $? == 0 ]
then sh test.sh
else
exit 1
fi

edited Oct 16, 2018 at 17:54

answered Oct 16, 2018 at 17:51

Mayank Porwal

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Comments

Mayank Porwal · Accepted Answer · 2018-11-23 13:55:03Z

1

Simply call the script this way: sh run.sh ¦¦ exit 1

edited Nov 23, 2018 at 13:55

Mayank Porwal

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answered Oct 16, 2018 at 19:40

Krassi Em

1928 bronze badges

1 Comment

Atif Over a year ago

is this function similar to ? sh run.sh if [ $? == 0 ] then sh test.sh else exit 1 fi

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