Get the exit code from a Batch file using Python

Question

I am trying to get the exit code from a Batch file. To be more specific I am having issues to get the ERRORLEVEL.

I tried using Popen, check_output,call, check_call:

   out = os.system(BatchFilePath)
   out, err = subprocess.Popen(BatchFilePath,stderr=subprocess.PIPE, shell=True).communicate()
   out,err = subprocess.Popen(BatchFilePath, stderr=subprocess.PIPE).communicate()
   out = subprocess.Popen(BatchFilePath,  shell=True).stderr
   out = os.system(BatchFilePath)
   out = subprocess.check_call(BatchFilePath)
   out = subprocess.call(BatchFilePath, shell=True)
   out = subprocess.check_output(buildPath, shell=True)

Which most of the times return empty or 0

I also tried using

SET ERRORLEVEL=1
exit /B !ERRORLEVEL!

but without luck. I also tried

    set RC=
    setlocal
    somecommand.exe
    endlocal & set RC=%ERRORLEVEL%
    exit /B %RC%

Anotherway to do it is to

out, err = subprocess.Popen(BatchFilePath,stdout=subrocess.PIPE,stderr=subprocess.PIPE, shell=True).communicate()

and searching for the string "ERROR" or "FAILURE" from the out variable.

On the other hand by doing so the user will not see all the echos from the batch file thus the screen will be empty without any messages until the batch file finish and print the appropriate message from my python script.

So I dont need to use the stdout=subrocess.PIPE option from the Popen because its printing all the echos from the batch.

I am working with the CMD and not the powershell. and I am using python 2.7

I searched in the google and here and I wasnt able to find anything that will help me. Any help will be appreciate.

olricson · Accepted Answer · 2018-10-25 11:02:37Z

1

To get the return code using subprocess.Popen use the poll() or wait() method.

Here an example using poll():

proc = subprocess.Popen('ls')
proc.communicate()
retcode = proc.poll()

Documentation here: https://docs.python.org/2/library/subprocess.html#subprocess.Popen.poll

As per your comment I checked using your batch script

SET ERRORLEVEL=1
exit /B !ERRORLEVEL!

It will work if you to replace ! with %

SET ERRORLEVEL=1
exit /B %ERRORLEVEL%

edited Oct 25, 2018 at 11:02

answered Oct 25, 2018 at 9:26

olricson

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4 Comments

isovitis Over a year ago

I tried that and I still got 0 as return code instead of 1. I made the batch file to fail in purpose.

olricson Over a year ago

Your batch file might be the problem. See my edited answer

isovitis Over a year ago

the only reason I had the '!' instead of '%' was because at the beginning of my batch file i have SETLOCAL enabledelayedexpansion

isovitis Over a year ago

I tried both ways but still I am getting 0 as Exit code instead of 1

isovitis · Accepted Answer · 2018-10-26 12:39:29Z

0

The solution to my problem it was really simple but quite nerve-wracking.

I replace the :

EXIT /B !ERRORLEVEL!

with

EXIT 1

and I used the

os.system(BatchFilePath)

over everything else.

Thank you @olricson, for taking the time to help me. I appreciate that.

answered Oct 26, 2018 at 12:39

isovitis

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