What is the difference between these two numpy arrays?
array([array([1,2,3]),array([4,5,6])])
and
array([[1,2,3],[4,5,6]])
How can we convert one to other?
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4 Answers
The result is the same. There's no need to convert anything:
A = np.array([np.array([1,2,3]), np.array([4,5,6])])
B = np.array([[1,2,3], [4,5,6]])
assert np.array_equal(A, B)
Comments
The result would be the same, but the standard would normally be:
array([[1,2,3],[4,5,6]])
4 Comments
Ahmad Khan
How is this the standard way?
ben_foster04
You come across this more often, more recognisable, if you will
Ahmad Khan
That doesn't make it a standard.
ben_foster04
I'm not specifically saying that it's a standard in that sense, I'm stating that you're more likely to come across this version than the other
As per the docs
numpy.array(object, dtype=None, copy=True, order='K', subok=False, ndmin=0)Parameters:
object : array_like
- An array, any object exposing the array interface, an object whose array method returns an array, or any (nested) sequence.
This means using:
array([array([1,2,3]),array([4,5,6])])
Is just redundant to:
array([[1,2,3],[4,5,6]])
As Numpy accepts nested lists (arrays) and will handle them accordingly.
Comments
These are just equivalent ways to create an array.
From the doc to np.array:
numpy.array(object, ...
object : array_like
An array, any object exposing the array interface, an object whose __array__ method returns an array, or any (nested) sequence
What you passed are both correct ways to initialize an array. Your first option is a nested sequence, the second one is a nested list.
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