How to check if Object keys are in Array filtered by Array key?

Question

I am working with an Angular 2 Ionic app -

Is there a way I can filter all persons by age in my personsArr and then find if any key in my personObj matches a personArr name and return a boolean?

I have an example array like:

personsArr = [{
        "name": "Ram",
        "email": "[email protected]",
        "age": 23
    },
    {
        "name": "peter",
        "email": "[email protected]",
        "age": 23
    },
    {
        "name": "John",
        "email": "[email protected]",
        "age": 33
    },
    {
        "name": "Bob",
        "email": "[email protected]",
        "age": 41
    }
]

and an object like this

personObj = {
    "peter": "helper",
    "Ram": "helper",
    "Bob": "helper"
}

How can I filter personsArr by age and then check if any key from personObj matches person name?

Pretty sure I can just do this with a loop, but is there a better way?

Appreciate any help or advise.

What are expected results to store the boolean? Please also show us what you tried with your loop approach — charlietfl
– charlietfl, Commented Nov 16, 2018 at 8:31

Alex G · Accepted Answer · 2018-11-16 09:27:33Z

You can try this, with filter and some. You filter by your condition and then check for matches on the object. Hope this helps.

const personsArr = [{
    "name": "Ram",
    "email": "[email protected]",
    "age": 23
    }, {
        "name": "peter",
        "email": "[email protected]",
        "age": 23
    }, {
        "name": "John",
        "email": "[email protected]",
        "age": 33
    }, {
        "name": "Bob",
        "email": "[email protected]",
        "age": 41
    }];

const personObj = { "Ram": "helper", "Bob": "helper" };

const personObj2 = { "Ram2": "helper", "Bob2": "helper" };

const checkArr = (age, arr, obj) => arr.filter((f) => f.age > age).some((d) => obj[d.name]);

console.log('Should be true');
console.log(checkArr(30, personsArr, personObj));
console.log('Should be false');
console.log(checkArr(30, personsArr, personObj2));

Nurbol Alpysbayev · Accepted Answer · 2018-11-16 08:40:33Z

2

Here you are

// Filter by age
const legalAge = 18 // for example
const boolean = personsArr
    // Actual filtering 
    .filter(p => p.age > legalAge)
    // Check if there is any `name` in personsArr matching any key in personObj
    .some(p =>
        Object.keys(personObj).some(pk => pk === p.name)
    )

// Sort by age (maybe you meant this instead of filtering)
personsArr.sort((a, b) => a.age > b.age ? 1 : -1)
const boolean2 = personsArr.some(p =>
    Object.keys(personObj).some(pk => pk === p.name)
)

answered Nov 16, 2018 at 8:40

Nurbol Alpysbayev

22.4k6 gold badges68 silver badges100 bronze badges

Comments

eXcalibur · Accepted Answer · 2018-11-16 08:34:21Z

1

If I understand you correctly then you need something like this:

const isFound = personsArr.some((item) => item.age > 30 && personObj.includes(item.name));

Of course item.age > 30 should be replaced with you filtering criteria.

answered Nov 16, 2018 at 8:34

eXcalibur

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Comments

Fenton · Accepted Answer · 2018-11-16 08:42:05Z

Whether you loop yourself or not, there is looping involved. The simplest answer is probably to use Array.filter.

personsArr.filter((val) => val.age === age && Object.keys(roles).indexOf(val.name) > -1);

Here is a complete example:

const personsArr = [
    { "name": "Ram", "email": "[email protected]", "age": 23 },
    { "name": "peter", "email": "[email protected]", "age": 23 },
    { "name": "John", "email": "[email protected]", "age": 33 },
    { "name": "Bob", "email": "[email protected]", "age": 41 }
];

const personObj = { "peter": "helper", "Ram": "helper", "Bob": "helper" };

function filter(age: number, roles: { [name: string]: string }) {
    const keys = Object.keys(roles);
    return personsArr.filter((val) => val.age === age && keys.indexOf(val.name) > -1);
}

// 0: Object { name: "Ram", email: "[email protected]", age: 23 }
// 1: Object { name: "peter", email: "[email protected]", age: 23 }
console.log(filter(23, personObj));

// 0: Object { name: "Bob", email: "[email protected]", age: 41 }
console.log(filter(41, personObj));

onejeet · Accepted Answer · 2018-11-16 08:51:53Z

1

var personsArr = [    
{"name":"Ram", "email":"[email protected]", "age":23},    
{"name":"peter", "email":"[email protected]", "age":23},  
{"name":"John", "email":"[email protected]", "age":33},    
{"name":"Bob", "email":"[email protected]", "age":41}   
];

var personObj = {"peter":"helper","Ram":"helper", "Bob":"helper"}

var newPersonsArr = personsArr.filter((person) => person.age<30);
var check = false;
for(var key in personObj) {
  newPersonsArr.map((person) => {
  if(person.name === key){
   check = true
  }
  });
}


console.log(check);

answered Nov 16, 2018 at 8:51

onejeet

1,1916 silver badges14 bronze badges

2 Comments

Fenton Over a year ago

As you are already using Array.filter for age you could check the name condition at the same time, thus reducing the amount of looping.

limit Over a year ago

This works - Is there anyway to break the loop after the first match? When I console log I am getting many additional loops of true.

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