How to convert string extracted by regex to integer in python?

Question

i'm trying to convert string to integer, but it's not that so easier than i'm thinking.

content = '''
<entry colname="1" morerows="1" morerowname="2"><p>111</p></entry>
<entry colname="2" rowname="2"><p></p></entry>'''


morerows = ''.join(re.findall('morerows="\d"', content))
morerows_n = int(''.join(re.findall('\d', morerows)))
print(morerows_n)

this results error as follow :

morerows_n = int(''.join(re.findall('\d', morerows)))
ValueError: invalid literal for int() with base 10: ''

where is wrong with that code? i've tried int() function but doesn't work and it's not float also.

any help?

It results in 1 for me

CertainPerformance
– CertainPerformance

2018-11-22 04:50:29 +00:00
Commented Nov 22, 2018 at 4:50 — CertainPerformance
– CertainPerformance, Commented Nov 22, 2018 at 4:50

supl · Accepted Answer · 2018-11-22 05:00:47Z

1

I guess there are non-integer characters in the morerows attribute in your real case.

How about this:

content = '''
<entry colname="1" morerows="1x" morerowname="2"><p>111</p></entry>
<entry colname="1" morerows="1" morerowname="2"><p>111</p></entry>
<entry colname="2" rowname="2"><p></p></entry>'''

morerows = ''.join(re.findall('morerows="[0-9]+"', content))
if morerows:
    morerows_n = int(''.join(re.findall('\d', morerows)))
print(morerows_n)

Use [0-9]+ instead of \d

answered Nov 22, 2018 at 5:00

supl

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2 Comments

Cho Over a year ago

I found what it's wrong with , yes you're right! some attributes have no morerows=" attribute in real case. so i use try and except. lot of thanks!

Cho Over a year ago

and i guess it's better to use \d than [0-9] cuz this number can be over 10. anyway thank you

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