How to skip null values in PostgreSQL query?

Question

I have a query in database table name "c_hw_day" in postgresql

select  pr.c_period_id,
        unnest(array_agg_mult(array[hd.wd1,hd.wd2,hd.wd3,hd.wd4,hd.wd5,hd.wd6,hd.wd7,hd.wd8,hd.wd9,hd.wd10,hd.hd1,hd.hd2,hd.hd2,hd.hd3,hd.hd4,hd.hd5,hd.hd6,hd.hd7,hd.hd8,hd.hd9,hd.hd10])) as wd_hd 
from    c_hw_day hd
  left join c_period pr on (hd.c_period_id = pr.c_period_id) 
group by 1

result like

ID	Weekend
1000051	2018-11-30 00:00:00
1000051
1000051
1000051	2018-12-07 00:00:00
1000051
1000051
1000051
1000051	2018-12-14 00:00:00

I want to skip the null value like

ID	Weekend
1000051	2018-11-30 00:00:00
1000051	2018-12-07 00:00:00
1000051	2018-12-14 00:00:00

unnest() together with array_agg() looks quite suspicious in the SELECT list — user330315
– user330315, Commented Dec 1, 2018 at 12:00

Gordon Linoff · Accepted Answer · 2018-12-01 11:43:39Z

2

I would would not do this using arrays. I would just use a lateral join:

select  pr.c_period_id, wd_hd
from c_hw_day hd left join
     c_period pr 
     on hd.c_period_id = pr.c_period_id lateral join
     (values (hd.wd1, hd.wd2, hd.wd3, hd.wd4, hd.wd5, hd.wd6, hd.wd7, hd.wd8, hd.wd9, hd.wd10, hd.hd1, hd.hd2, hd.hd2, hd.hd3, hd.hd4, hd.hd5, hd.hd6, hd.hd7, hd.hd8, hd.hd9, hd.hd10
     ) v(hd)
where hd is not null;

This logic is much clearer. Without the outer group by, I suspect it is faster as well.

answered Dec 1, 2018 at 11:43

Gordon Linoff

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Comments

are · Accepted Answer · 2018-12-01 08:30:28Z

1

the most lasiest way - put your query into subquery if you don't have a lot of data will be ok

select * from (
    select  pr.c_period_id,
           unnest(array_agg_mult(array[hd.wd1,hd.wd2,hd.wd3,hd.wd4,hd.wd5,hd.wd6,hd.wd7,hd.wd8,hd.wd9,hd.wd10,hd.hd1,hd.hd2,hd.hd2,hd.hd3,hd.hd4,hd.hd5,hd.hd6,hd.hd7,hd.hd8,hd.hd9,hd.hd10])) as wd_hd 
    from    c_hw_day hd
      left join c_period pr on (hd.c_period_id = pr.c_period_id) 
    group by 1
)q1
where wd_hd is not null

answered Dec 1, 2018 at 8:30

are

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