Python Invalid Syntax error for function Default Argument

Question

Here is my code, I don't see any issue with this.

def test_methopd(async=False):
    pass

When I import the module I am getting following error.

$ python3 -c "import test"
 File "/Users/gaurang.shah/Documents/ctc/code/ci-cd-framework/atf/clients/test.py", line 1
    def test_methopd(async=False):
                         ^
SyntaxError: invalid syntax

The code works perfectly fine with Python 3.4.9 however gives error with Python 3.7.0

Community · Accepted Answer · 2020-06-20 09:12:55Z

2

As of Python 3.7 async is a reserved word which cannot be used as an identifier (such as a parameter name)

PEP describing this change: https://www.python.org/dev/peps/pep-0492/#deprecation-plans

Depreciation Plans

async and await names will be softly deprecated in CPython 3.5 and 3.6. In 3.7 we will transform them to proper keywords.

This is also reflected in the online docs: https://docs.python.org/3/reference/lexical_analysis.html#keywords

edited Jun 20, 2020 at 9:12

CommunityBot

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answered Dec 6, 2018 at 17:14

UnholySheep

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